Answer:
27
Step-by-step explanation:
Since 3^6 is only divisible by 3 and powers of 3(including 1) the gcd of 3^6 and 6^3 mus be a power of 3 hence we need to find the highest powers of 3 that divide 6^3 and that divide 3^6, which are respectively 3^3 and 3^6, hence, taking the smaller one (since we want it to divide both), our answer is 3^3=27.
Multiply everything by -3 so it will be n-15>4 then add 15 to both sides so it will be n>19 and thats the answer.
So what is the question you are asking here
