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Vlad [161]
3 years ago
9

describe the horizontal and/or vertical shifts used to transform the equation y=|x| to the equation y=|x|+4

Mathematics
1 answer:
netineya [11]3 years ago
6 0
It will move 4 to the right horizontally
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the sun shines on a flagpole, causing a shadow to be cast on the ground. the distance from the base of the pole to the tip of th
kobusy [5.1K]

Answer:

30.17feet high

Step-by-step explanation:

Given the following

the distance from the base of the pole to the tip of the shadow = 49feet (hypotenuse)

angle of elevation = 38°

Required

Height of the flagpole (opposite)

Using the SOH CAH TOA identity

Sin theta = opposite/hypotenuse

Sin 38 = H/49

H = 49sin38

H = 49(0.6157)

H = 30.17feet

Hence the flagpole is 30.17feet high

7 0
3 years ago
Mala ran 30 laps in week one and will increase the number of laps she runs by 2 each week. Coby runs 16 laps in week one and wil
matrenka [14]
The equations are 30+2x and 16+5x. i plug random numbers into x until you fint the correct answer. the answer is 5.

7 0
3 years ago
(x^2 + 5x + 2) – (5x^2 – x – 2) =
zlopas [31]

Answer:

{ \tt{( {x}^{2} + 5x + 2) - (5 {x}^{2} - x - 2)  }} \\  = { \tt{(1 - 5) {x}^{2}  + (5 + 1)x + (2 + 2)}} \\  = { \tt{ - 4 {x}^{2} + 6x + 4 }} \\  = { \tt{ - 2(2 {x}^{2} - 3x - 2) }}

3 0
3 years ago
Read 2 more answers
A circle has an area of 314.1592. What is the diameter? (round to the nearest whole number)
ad-work [718]

Answer:

20

Step-by-step explanation:

The area of a circle is equal to pi*radius^2

We can then write this as

314.1592=π*r^2

We then divide pi to get

100=r^2

take the square root and you find that the radius equals around 10

The diameter is always equal to the radius times two which means that the diameter is 20

hope this helps

8 0
3 years ago
Hi, I am taking PSAT and I am working on the math section. I need help with answering this math type of question. Please give th
ValentinkaMS [17]

By using the concept of uniform rectilinear motion, the distance surplus of the average race car is equal to 3 / 4 miles. (Right choice: A)

<h3>How many more distance does the average race car travels than the average consumer car?</h3>

In accordance with the statement, both the average consumer car and the average race car travel at constant speed (v), in miles per hour. The distance traveled by the vehicle (s), in miles, is equal to the product of the speed and time (t), in hours. The distance surplus (s'), in miles, done by the average race car is determined by the following expression:

s' = (v' - v) · t

Where:

  • v' - Speed of the average race car, in miles per hour.
  • v - Speed of the average consumer car, in miles per hour.
  • t - Time, in hours.

Please notice that a hour equal 3600 seconds. If we know that v' = 210 mi / h, v = 120 mi / h and t = 30 / 3600 h, then the distance surplus of the average race car is:

s' = (210 - 120) · (30 / 3600)

s' = 3 / 4 mi

The distance surplus of the average race car is equal to 3 / 4 miles.

To learn more on uniform rectilinear motion: brainly.com/question/10153269

#SPJ1

4 0
1 year ago
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