we know that
The measure of the external angle is the semidifference of the arcs that it covers
so
∠MLN=(1/2)*(mayor arc MN-minor arc MN)
Let
x------> minor arc MN
major arc MN=360-x
substitute in the formula above
∠MLN=(1/2)*(mayor arc MN-minor arc MN)
75.86=(1/2)*(360-x-x)------> 151.72=(360-2x)------>360-151.72=2x
x=104.14°
therefore
the answer is
the measure of arc MN (minor arc) is 104.14°
1. Distribute
1/125 x 5n - 1/125
2. Simplify 1/125 x 5n to n/25
n/25 - 1/125
For 12 minutes because 23 x 12 is 2.76 and 25 minus 22.24 is 2.76
Answer:
45.3 miles/h
Step-by-step explanation:
The answer is 45.3 miles/h
X = -8.
subtract 19.
-X = 8
divide by -1.
X = -8