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dedylja [7]
2 years ago
10

A helicopter floats 120m above a helipad, a dog is 85m from the helipad, if the dog could fly, how far would it have to fly to g

et to helicopter?
Mathematics
1 answer:
suter [353]2 years ago
3 0

<em>If the dog could fly, it would need to fly 147 meters to catch the helicopter</em>

This is a rather easy and straightforward question. We are going to solve it using Pythagoras theorem. We can interpret the question to be in a triangle where the height of the helicopter above the helipad and away from the dog is the right angle. This also means that the distance needed, between the dog and the helicopter is the hypotenuse.

Using pythagoras theorem, we have

120² + 85² = c²

c² = 14400 + 7225

c² = 21625

c = \sqrt{21625}

c = ±147 meters.

Since distance cant be in the negative, our answer is 147 m

read more about pythagoras theorem here brainly.com/question/15138986

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According to the line plot, what is the total weight gained by the dogs that gained 1/8 f a pound or 3/4 of a pound?
erik [133]

3 1/8

First you take the all the dogs that gained 3/4 (which is 4)
Then you multiply it by 4

3/4x4=3
Then you add the dogs that gained 1/8 of a pound

3+1/8=3 1/8

4 0
2 years ago
Rewrite the product as a sum: 10cos(5x)sin(10x)
mote1985 [20]

Answer:

10cos(5x)sin(10x) =  5[sin (15x) + sin (5x)]

Step-by-step explanation:

In this question, we are tasked with writing the product as a sum.

To do this, we shall be using the sum to product formula below;

cosαsinβ = 1/2[ sin(α + β) - sin(α - β)]

From the question, we can say α= 5x and β= 10x

Plugging these values into the equation, we have

10cos(5x)sin(10x) = (10) × 1/2[sin (5x + 10x) - sin(5x - 10x)]

= 5[sin (15x) - sin (-5x)]

We apply odd identity i.e sin(-x) = -sinx

Thus applying same to sin(-5x)

sin(-5x) = -sin(5x)

Thus;

5[sin (15x) - sin (-5x)] = 5[sin (15x) -(-sin(5x))]

= 5[sin (15x) + sin (5x)]

Hence,  10cos(5x)sin(10x) =  5[sin (15x) + sin (5x)]

8 0
3 years ago
What are all the subsets of {5,9,13}
Naddika [18.5K]
All The Subsets

For theset {a,b,c}:

<span>The empty set {} is a subset of {a,b,c}And these are subsets: {a}, {b} and {c}And these are also subsets: {a,b}, {a,c} and {b,c}And {a,b,c} is a subset of {a,b,c}</span>

And when we list all the subsets of S={a,b,c} we get the Power Set of {a,b,c}:

P(S) = { {}, {a}, {b}, {c}, {a, b}, {a, c}, {b, c}, {a, b, c} }

Think of it as all the different ways we can select the items (the order of the items doesn't matter), including selecting none, or all.

Example: The shop has banana, chocolate and lemon ice cream.

 

What do you order?

<span>Nothing at all: {}Or maybe just banana: {banana}. Or just {chocolate} or just {lemon}Or two together: {banana,chocolate} or {banana,lemon} or {chocolate,lemon}Or all three! {banana, chocolate,lemon}</span>

Question: if the shop also has strawberry flavor what are your options? Solution later.

How Many Subsets

Easy! If the original set has n members, then the Power Set will have <span>2n</span> members

Example: in the {a,b,c} example above, there are three members (a,b and c).

So, the Power Set should have 23 = 8, which it does!

Notation

The number of members of a set is often written as |S|, so when S has n members we can write:

|P(S)| = 2n

Example: for the set S={1,2,3,4,5} how many members will the power set have?

Well, S has 5 members, so:

|P(S)| = 2n = 25 = 32

You will see in a minute why the number of members is a power of 2

It's Binary!

And here is the most amazing thing. To create the Power Set, write down the sequence of binary numbers (using n digits), and then let "1" mean "put the matching member into this subset".

So "101" is replaced by 1 a, 0 b and 1 c to get us {a,c}

Like this:

<span><span> abcSubset</span><span>0000{ }</span><span>1001{c}</span><span>2010{b}</span><span>3011{b,c}</span><span>4100{a}</span><span>5101{a,c}</span><span>6110{a,b}</span><span>7111{a,b,c}</span></span>

Well, they are not in a pretty order, but they are all there.

Another Example<span>Let's eat! We have four flavors of ice cream: banana, chocolate, lemon, and strawberry. How many different ways can we have them?Let's use letters for the flavors: {b, c, l, s}. Example selections include:<span>{} (nothing, you are on a diet){b, c, l, s} (every flavor){b, c} (banana and chocolate are good together)etc</span></span>Let's make the table using "binary":<span><span> bclsSubset</span><span>00000{}</span><span>10001{s}</span><span>20010{l}</span><span>30011{l,s}</span><span>...... etc ..... etc ...</span><span>121100{b,c}</span><span>131101{b,c,s}</span><span>141110{b,c,l}</span><span>151111{b,c,l,s}</span></span>

And the result is (more neatly arranged):

P = { {}, {b}, {c}, {l}, {s}, {b,c}, {b,l}, {b,s}, {c,l}, {c,s}, {l,s}, {b,c,l}, {b,c,s}, 
{b,l,s}, {c,l,s}, {b,c,l,s} }


<span><span>SymmetryIn the table above, did you notice that the first subset is empty and the last has every member?But did you also notice that the second subset has "s", and the second last subset has everything except "s"?</span><span>  </span><span>In fact when we mirror that table about the middle we see there is a kind of symmetry.This is because the binary numbers (that we used to help us get all those combinations) have a beautiful and elegant pattern.</span></span>A Prime Example

The Power Set can be useful in unexpected areas.

I wanted to find all factors (not just the prime factors, but all factors) of a number.

I could test all possible numbers: I could check 2, 3, 4, 5, 6, 7, etc...

That took a long time for large numbers.

But could I try to combine the prime factors?

Let me see, the prime factors of 510 are 2×3×5×17 (using prime factor tool).

So, all the factors of 510 are:

<span>2, 3, 5 and 17,2×3, 2×5 and 2×17 as well, and2×3×5 and 2×3×17 and ..... aha! Just like ice cream I needed a Power Set!</span>

And this is what I got:

<span><span> 2,3,5,17SubsetFactors of 510</span><span>00000{ }1</span><span>10001{17}17</span><span>20010{5}5</span><span>30011{5,17}5 × 17 = 85</span><span>40100{3}3</span><span>50101{3,17}3 × 17 = 51</span><span> ... etc ...... etc ...... etc ...</span><span>151111{2,3,5,17}2 × 3 × 5 × 17 = 510</span></span>


And the result? The factors of 510 are 1, 2, 3, 5, 6, 10, 15, 17, 30, 34, 51, 85, 102, 170, 255 and 510 (and −1, −2, −3, etc as well). See the All Factors Tool.

Automated

I couldn't resist making Power Sets available to you in an automated way.

So, when you need a power set, try Power Set Maker.

6 0
3 years ago
Read 2 more answers
What percent of the muffins were carrots
Readme [11.4K]

Answer:

0%

Step-by-step explanation:

Muffins aren't carrots, unless they are carrot muffins.

6 0
2 years ago
An unknown fraction is between 0 and 1. Which is true about the equivalent percent and decimal?
horsena [70]
Its equivalent percent is less than 100% and its equivalent decimal is less than 0.99 or less.

For example, 1/2 is a fraction between 0 and 1. Its percentage is 50%, which is less than 100%. Its decimal is 0.50, which is less than 1 or 0.99
3 0
3 years ago
Read 2 more answers
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