1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
sleet_krkn [62]
3 years ago
11

How does the pattern of embryological development provide further evidence that organisms have descended from a common ancestor?

Biology
2 answers:
snow_tiger [21]3 years ago
8 0
<span>A big variety of organisms’ genomes have genes that control the organisms’ development at different stages. The remains of ancestral traits usually appear at different stages of the embryological development. For example, hair growth and loss, the development and deformation of the yolk sac or appearance and disappearance of gill structures in the embryo development of vertebrates.</span>
GalinKa [24]3 years ago
3 0
Similar patterns of embryological development provide further evidence that organisms have descended from a common ancestor.  All species share a common descent, a group of organisms share common descent if they have a common ancestor. There is strong quantitative support for the theory that all living organisms on Earth are descended from a common ancestor.
You might be interested in
Explain how the muscular and skeletal systems work together within the body.
Blababa [14]
Your skeletal system gives the body structure and support while your muscular system helps provide movement.
4 0
3 years ago
Cocaine exerts its pleasurable effects on the brain by:
Semenov [28]

It disconnects the brain's dopamine system.

Further explanation

Cocaine

Cocaine is a capably addictive stimulant medication. For a great many years, individuals in South America have bitten and ingested coca leaves which is source of cocaine, for their stimulant effects. In the mid-1900s, refined cocaine was the primary dynamic fixing in numerous tonics and elixirs created to treat a wide assortment of diseases and was even a fixing in the early plans of Coca-Cola. Prior to the advancement of manufactured specialists utilized cocaine for the relief of pain. However, examine has since demonstrated that cocaine is an effectively addictive substance that can change cerebrum structure and capacity whenever utilized over and over.

Functions of cocaine

It shows very quickly effect after a solitary portion and vanish inside a couple of minutes to 60 minutes. Limited quantities of cocaine for the most part make the person feel euphoric, enthusiastic, loquacious, rationally caution, and easily affected to sight, sound, and contact. The medication can likewise briefly diminish the requirement for sustenance and sleep. Some clients find that cocaine encourages them perform straightforward physical and scholarly assignments all the more rapidly, in spite of the fact that others experience the contrary impact.

Effect of cocaine on dopamine

Cocaine particles block the dopamine transporters which shut down the neuron's capacity to take-up the additional dopamine inside the synaptic parted. This outcomes in expanded degrees of the synapse dopamine present in the extracellular spaces among these neurons.

Answer details

Subject: Biology

Level: College

Key words

  • Cocaine
  • Functions of cocaine
  • Effect of cocaine on dopamine

Learn more to evaluate

brainly.com/question/12887489

brainly.com/question/10560288

brainly.com/question/12603071

7 0
3 years ago
Read 2 more answers
Which of the following enzymes has an optimum working pH of
vitfil [10]

Answer:

Trypsin

Explanation:

6 0
3 years ago
The Offspring produced by a cross between two given types of plants can be any of the three genotypes denoted by A, B, and C. A
ratelena [41]

Complete question:

The offspring produced between two given types of plants can be any of the three genotypes, denoted by A, B and C. A theoretical model of gene inheritance suggests that the offspring of types A, B and C should be in a 1:2:1 ratio (meaning 25% A, 50% B, and 25% C). For experimental verification, 100 plants are bred by crossing the two given types. Their genetic classifications are recorded in the table below.

<em><u>Genotype       Observed frequency</u></em>

    A             →        18 individuals

    B             →        55 individuals

    C             →        27 individuals

Do these contradict the genetic model?  

Use a 0.05 level of significance.

Determine the chi-square test statistic.

Answer:

Do these contradict the genetic model? No, according to the chi-square test, there is not enough evidence to reject the null hypothesis of the population being in equilibrium.  

Explanation:

<u>Available data</u>:

  • Crossed genotypes: two
  • Genotypes among the offspring; Three → A, B, and C
  • Expected phenotypic ratio → 1:2:1
  • Total number of individuals, N = 100
  • A = 18 individuals
  • B = 55 individuals
  • C = 27 individuals

So, let us first state the hypothesis:

  • H₀= the population is equilibrium for this locus → F(A) = 25%,  F(B) = 50%, F(C) = 25%  
  • H₁ = the population is not in equilibrium

Now, let us calculate the number of expected individuals, according to their expected ratio.

4 -------------- 100% -------------100 individuals

1 ---------------  25% -------------X = 25 individuals A

2 --------------  50% -------------X = 50 individuals B

1----------------- 25%--------------X = 25 individuals C

<u>                                                   A                             B                           C</u>

  • Observed                         18                            55                         27
  • Expected                         25                           50                         25
  • (Obs-Exp)²/Exp                1.96                        0.5                        0.16

<u>(Obs-Exp)²/Exp</u>

A)  (18 - 25)²/25 = 49/25 = 1.96

B)  (55 - 50)² / 50 = 25/50 = 0.5

C)  (27 - 25)²/25 = 4/25 = 0.16

Chi square = X² = Σ(Obs-Exp)²/Exp  

  • ∑ is the sum of the terms
  • O are the Observed individuals: 2 in chamber B, and 18 in chamber A.  
  • E are the Expected individuals: 10 in each chamber  

X² = ∑ ((O-E)²/E) = 1.96 + 0.5 + 0.16 = 2.62

Freedom degrees = 2

Significance level, 5% = 0.05  

Table value/Critical value = 5.99

X² < Critical value

2.62 < 5.99    

<em>These results suggest that there is </em><u><em>not enough evidence to reject</em></u><em> the null hypothesis. We can assume that </em><u><em>the locus under study in this population is in equilibrium H-W.  </em></u>

 

6 0
3 years ago
What are the special features of a sperm cell
Airida [17]
<span>Long tail for swimming
<span>Head for getting into the female cell

Hope this helps you ! :') </span></span>
3 0
3 years ago
Read 2 more answers
Other questions:
  • What does the term "limiting factors " mean? name did examples for a jackrabbit in the desert.
    14·2 answers
  • About one hundred thousand years ago, very fluid lava started erupting slowly and gently from a place near a plate boundary. Wha
    8·1 answer
  • 20 points help PLEASE!!! Match the following items.
    12·1 answer
  • Name the two types of variables in an experiment<br> plz answer
    12·1 answer
  • Explain how important is the role of the parents during the earlier stage of development?​
    11·1 answer
  • When compared to Eurkaryotic cells , prokaryotic cells are almost always
    7·1 answer
  • Explain briefly four<br> why, peasant<br> farmers find it diffcult to get<br> farm credit
    15·1 answer
  • It is difficult to observe individual chromosomes
    13·1 answer
  • How does nectar increase the ability of plants to reproduce?
    14·2 answers
  • Matter is comprised of of atoms <br> is it <br> hypothesis<br> theory<br> law<br> fact <br> belife
    11·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!