Answer:
The reaction isn't yet at equilibrium. The overall reaction will continue to move in the direction of the products.
Assumption: this system is currently at 
.
Explanation:
One way to tell whether a system is at its equilibrium is to compare its reaction quotient 
with the equilibrium constant 
of the reaction.
The equation for is quite similar to that for . The difference between the two is that requires equilibrium concentrations, while can be calculated even when the system is on its way to equilibrium.
For this reaction,
![\displaystyle Q = \rm \frac{[CS_2]\cdot [H_2]^{4}}{[CH_4]\cdot [H_2S]^{2}}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20Q%20%3D%20%5Crm%20%5Cfrac%7B%5BCS_2%5D%5Ccdot%20%5BH_2%5D%5E%7B4%7D%7D%7B%5BCH_4%5D%5Ccdot%20%5BH_2S%5D%5E%7B2%7D%7D)
.
Given these concentrations,
![\displaystyle Q = \rm \frac{[CS_2]\cdot [H_2]^{4}}{[CH_4]\cdot [H_2S]^{2}} =\frac{1.51\times (1.08)^{4}}{1.15\times (1.20)^{2}} \approx 1.72](https://tex.z-dn.net/?f=%5Cdisplaystyle%20Q%20%3D%20%5Crm%20%5Cfrac%7B%5BCS_2%5D%5Ccdot%20%5BH_2%5D%5E%7B4%7D%7D%7B%5BCH_4%5D%5Ccdot%20%5BH_2S%5D%5E%7B2%7D%7D%20%3D%5Cfrac%7B1.51%5Ctimes%20%281.08%29%5E%7B4%7D%7D%7B1.15%5Ctimes%20%281.20%29%5E%7B2%7D%7D%20%5Capprox%201.72)
.
The question states that at , 
. Assume that currently this system is also at . (The two temperatures need to be the same since the value of depends on the temperature.)
It turns out that 
. What does this mean?
- First, the system isn't at equilibrium.
- Second, if there's no external changes, the system will continue to move towards the equilibrium. Temperature might change. However, eventually will be equal to , and the system will achieve equilibrium.
In which direction will the system move? At this moment, 
. As time proceeds, the value of will increase so that it could become equal to . Recall that is fraction.
When the value of increases, either its numerator becomes larger or its denominator becomes smaller, or both will happen at the same time. However,
- Concentrations on the numerator of are those of the products;
- Concentrations on the denominator of are those of the reactants.
As time proceeds,
- the concentration of the products will increase, while
- the concentration of the reactants will decrease.
In other words, the equilibrium will move towards the products.
Answer:
The correct option is: stable environment
Explanation:
According to the Darwin's theory, natural selection is the concept by which all the small useful variations of traits are preserved.
According to Darwin, there are three <u>necessary and sufficient conditions</u> for the occurrence of natural selection:
1. struggle for existence
2. variation
3. inheritance
These conditions are said to be necessary because if these conditions are not satisfied then natural selection does not occur.
These conditions are said to be sufficient because if these conditions are satisfied, then natural selection will most definitely occur.
The final pressure of the gas in the container is 4 atm
From the question given above, the following data were obtained:
Initial volume (V₁) = 4 L
Initial temperature (T₁) = 300 K
Initial pressure (P₁) = 1 atm
Final temperature (T₂) = 600 K
Final volume (V₂) = 2 L
<h3>Final pressure (P₂) =?</h3>
- Using the combine gas equation, we can obtain the final pressure of the gas as illustrated below:
Cross multiply
300 × 2 × P₂ = 4 × 600
600 × P₂ = 2400
Divide both side by 600
<h3>P₂ = 4 atm</h3>
Therefore, the final pressure of gas is 4 atm.
Learn more: brainly.com/question/23558057
Answer:
D. chemical alters the atomic structure of a substance, while physical does not
hope this helps!
We can use the ideal gas law equation to find the volume of the balloon.
PV = nRT
where
P - pressure - 0.992 atm x 101 325 Pa/atm = 100 514 Pa
V - volume
n - number of moles - 8.80 mol
R - universal gas constant - 8.314 Jmol⁻¹K⁻¹
T - temperature in kelvin - 25 °C + 273 = 298 K
Substituting these values in the equation
100 514 Pa x V = 8.80 mol x 8.314 Jmol⁻¹K⁻¹ x 298 K
V = 217 L
volume of balloon is 217 L
