Question

A sample of a gas in a 4L container at 300K has a pressure of 1 atm. If the

Answer 1

The final pressure of the gas in the container is 4 atm

From the question given above, the following data were obtained:

Initial volume (V₁) = 4 L

Initial temperature (T₁) = 300 K

Initial pressure (P₁) = 1 atm

Final temperature (T₂) = 600 K

Final volume (V₂) = 2 L

Final pressure (P₂) =?

• Using the combine gas equation, we can obtain the final pressure of the gas as illustrated below:

$\frac{P_{1} V_{1} }{T_{1}} = \frac{P_{2} V_{2}}{T_{2}}\\\\\frac{1 * 4}{300} = \frac{P_{2} * 2}{600}$

Cross multiply

300 × 2 × P₂ = 4 × 600

600 × P₂ = 2400

Divide both side by 600

$P_{2} = \frac{2400}{600}$

P₂ = 4 atm

Therefore, the final pressure of gas is 4 atm.

Learn more: brainly.com/question/23558057