First, you need to find the number of moles of OH⁻ in a 250mL solution of 0.100M OH⁻. To do this, multiply 0.250L by 0.100M to get 0.025mol OH⁻. Then you use the fact that 1 mole of Sr(OH₂)·8H₂O contains 2 moles of OH⁻ which means that 0.0125mol of Sr(OH)₂·8H₂O contains 0.025mol OH⁻ (0.025/2=0.0125). Then to find the amount of Sr(OH)₂·8H₂O is needed you multiply its molar mass (265.76g/mol) by 0.0125mol to get 3.322g.
Therefore you need 3.322g of Sr(OH)₂·8H₂O.
I hope that helps. Let me know if anything is unclear.
Answer : The time passed in days is 28.6 days.
Explanation :
Half-life = 14.3 days
First we have to calculate the rate constant, we use the formula :
Now we have to calculate the time passed.
Expression for rate law for first order kinetics is given by:
where,
k = rate constant =
t = time passed by the sample = ?
a = let initial amount of the reactant = 100 g
a - x = amount left after decay process = 100 - 75.0 = 25.0 g
Now put all the given values in above equation, we get
Therefore, the time passed in days is 28.6 days.
Answer:
plyojexity
Explanation:
222^ -67'h~=H87
KJ energy is 5761 g and uses folytics and eats up the waizamorts of golerigrofy
Answer:
it is already balanced bro
Answer:
First one is: ammonia
Second one is: calcium hydroxide
Explanation: