Answer:
$1583.60 in interest (i), in addition to her savings (s) of $31,672.00
$33,255.60 total (t) after one year.
Step-by-step explanation:
$1583.60(i)(5%)+$31,672.00(s)= $33,255.60(t)
Answer:
The test value is z = -1.31.
Step-by-step explanation:
The Eagle Ridge Contractors Association claims the average price of a home in their subdivision is $125,150.
This means that the null hypothesis is that the mean is this value, that is:

The Eagle Ridge Home Owners Association is interested in knowing if the costs of homes for sale in this subdivision are actually lower than claimed.
This means that at the alternate hypotehsis we test that the mean is lower than that value, that is:

The test statistic is:

In which X is the sample mean,
is the value tested at the null hypothesis,
is the standard deviation and n is the size of the sample.
125150 is tested at the null hypothesis:
This means that 
Standard deviation of $7,350.
This means that 
A sample of 36 homes for sale in this subdivision had an average selling price of $123,550.
This means that 
Compute the test value.



The test value is z = -1.31.
<span>They share a vertex and side, but do not overlap
Hope this helps</span>
I think I can.
Let's do it together:
Let's call the number of buses 'B', and the number of vans 'V'.
(Pretty clever so far, don't you think ?)
OK. What do we know ?
-- Each bus holds 51 passengers. The number of passengers in 'B' buses is 51B.
-- A van holds 10 passengers. The number of passengers in 'V' vans is 10V.
-- The total number of passengers ... (51B + 10V) ... is 142.
-- The total number of vehicles ... (B + V) ... is 6, because there are 6 drivers.
Can you make a system of equations out of that information yet ?
How about this:
51B + 10V = 142
B + V = 6
I really think you can handle it from here.
=======================================
Multiply the 2nd equation by 10 :
51B + 10V = 142
10B + 10V = 60
Subtract the 2nd equation from the 1st one:
41B = 82
Divide each side by 41: <em> B = 2 buses</em>
2 buses . . . . 2 drivers . . . . 2 x 51 = 102 passengers
4 vans . . . . . 4 drivers . . . . . 4 x 10 = 40 passengers
6 vehicles . . . 6 drivers . . . . . 102 + 40 = 142 passengers