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hoa [83]
3 years ago
14

The Eagle Ridge Contractors Association claims the average price of a home in their subdivision is $125,150 with a standard devi

ation of $7,350. A sample of 36 homes for sale in this subdivision had an average selling price of $123,550. The Eagle Ridge Home Owners Association is interested in knowing if the costs of homes for sale in this subdivision are actually lower than claimed? Compute the test value.
Mathematics
1 answer:
jonny [76]3 years ago
5 0

Answer:

The test value is z = -1.31.

Step-by-step explanation:

The Eagle Ridge Contractors Association claims the average price of a home in their subdivision is $125,150.

This means that the null hypothesis is that the mean is this value, that is:

H_0: \mu = 125150

The Eagle Ridge Home Owners Association is interested in knowing if the costs of homes for sale in this subdivision are actually lower than claimed.

This means that at the alternate hypotehsis we test that the mean is lower than that value, that is:

H_a: \mu < 125150

The test statistic is:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

In which X is the sample mean, \mu is the value tested at the null hypothesis, \sigma is the standard deviation and n is the size of the sample.

125150 is tested at the null hypothesis:

This means that \mu = 125150

Standard deviation of $7,350.

This means that \sigma = 7350

A sample of 36 homes for sale in this subdivision had an average selling price of $123,550.

This means that n = 36, X = 123550

Compute the test value.

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

z = \frac{123550 - 125150}{\frac{7350}{\sqrt{36}}}

z = -1.31

The test value is z = -1.31.

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Slope = -3/5

Step-by-step explanation:

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m = -2 - 1 / 1 - -4

m = -3 / 1 + 4

m = -3 / 5

You can check the work by counting rise (-3 which means 3 units down) over run (5 which means 5 units to the right)

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The circumference of a circular rug is 24.8 meters. What is the area of the rug? Use 3.1 for pi
mestny [16]

Answer:

The area of rug is 48.9 m^2

Step-by-step explanation:

Let's assume radius of rug is r m

we know formula for circumference as

C=2\pi r

we are given

C=24.8

and then we can solve for r

24.8=2\pi r

r=3.947

now, we can use area formula

A=\pi r^2

we can plug r

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The smallest object visible with your eyes is similar to the width of a piece of hair, which is 1×10−4 meters wide. Using an opt
Sloan [31]

Answer:

B. 5\times10^{2}

Step-by-step explanation:

We are told that the smallest object visible with our eyes is similar to the width of a piece of hair, which is 1\times 10^{-4} meters wide.

Using an optical microscope, we can see items up to 2\times 10^{-7} meters wide.

To find the objects we can see with our eyes are how much larger than the objects we can see with an optical microscope, we can set an equation as:

\frac{\text{The width of the object we can see with our eyes}}{\text{The width of the objects we can see with microscope}}=\frac{1*10^{-4}}{2*10^{-7}}

Using the exponent rule of quotient \frac{a^m}{a^n}=a^{m-n} we will get,

\frac{\text{The width of the object we can see with our eyes}}{\text{The width of the objects we can see with microscope}}=\frac{1}{2}*10^{-4-(-7)}

\frac{\text{The width of the object we can see with our eyes}}{\text{The width of the objects we can see with microscope}}=0.5*10^{-4+7}

\frac{\text{The width of the object we can see with our eyes}}{\text{The width of the objects we can see with microscope}}=0.5*10^{3}

\frac{\text{The width of the object we can see with our eyes}}{\text{The width of the objects we can see with microscope}}=0.5*10\times 10^{3-1}

\text{The object we can see with our eyes}=5\times10^{2}*\text{The objects we can see with microscope}

Therefore, the objects we can see with our eyes are 5\times10^{2} times larger than the objects we can see with an optical microscope and option B is the correct choice.

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