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Vsevolod [243]
3 years ago
14

What is the line symmetry for a parabola whose equation is y=2x^2-4x+1

Mathematics
1 answer:
kompoz [17]3 years ago
3 0
Hello,

y=2x²-4x+1
==>y=2(x²-2x+1-1)+1
==>y=2(x-1)²-1

The line symmetry is x=1

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7/12,  3/4,  4/7,  5/8,  4/7

Answer:  

Order from Least to Greatest

4/7    =       4/7     <       7/12    <    5/8   <   3/4  

Showing Work  

Rewriting as fractions if necessary:  

7/12, 3/4, 4/7, 5/8, 4/7  

The least common denominator (LCD) is: 168.  

Rewriting as equivalent fractions with the LCD:  

98/168, 126/168, 96/168, 105/168, 96/168  

Ordering these fractions by the numerator in order from least to greatest:  

96/168    =    96/168     <     98/168    < 105/168    < 126/168  

Therefore, your input in order from least to greatest is:

Answer   =======>   4/7    =   4/7    <    7/12    <     5/8    < 3/4


B):  1.35,   5/4,   1.349,  6/5, 7/6

Number of inputs ====>  5

Answer => Ascending Order:  Least to Greatest =====>  7/6, 6/5, 5/4, 1.349, 1.35



C):   0.819,  0.8199, 81/100, 815/1000

Number of Inputs  ======>    4

Answer  ==> Ascending order (Least to Greatest ====>    81/100, 815/1000, 0.819, 0.8199



D):    3  4/7, 245/70, 3.572, 90/29

Number of Inputs:  4

Answer ==>  Ascending Order(Least to Greatest) ==> 90/29, 245/70, 3.572, 3 4/7




Hope that helps!!!!                                              : )

     


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