1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
irakobra [83]
3 years ago
10

What is the mean of the following set of data? Round your answer to two decimal places.

Mathematics
1 answer:
kolezko [41]3 years ago
7 0
The mean is 73.44<span>

</span>
You could've found this by adding up all the values in the data set, then dividing by how many numbers were in the data set!

66+81+60+72+79+83+60+92+68 = 661

661 ÷ 9 = 73.44
You might be interested in
<img src="https://tex.z-dn.net/?f=%20-%20%20%5Cfrac%7B2%7D%7B3%7D%20%20%2B%204%20%5Ctimes%20%5Cfrac%7B1%7D%7B3%7D%20" id="TexFor
pshichka [43]

Answer:

2/3

Step-by-step explanation:

You first multiply 4x1/3 which equals 4/3. Now you do -2/3+4/3=2/3. Hope this helps!

3 0
3 years ago
Read 2 more answers
Antoinette solves the linear equation 3(x-3)+2x+9 - 2x+ 2(x-1) using the steps shown below.
Oxana [17]

Step-by-step explanation:

3(x - 3) + 2x + 9 - 2x + 2(x - 1)

3x - 9 + 2x + 9 - 2x + 2x - 2

Solving like terms

5x - 2

5x = 2

x = 2/ 5

I think she incorrectly applied the multiplication and division properties of equality

4 0
3 years ago
Read 2 more answers
We paid $8 for 2 hamburgers, which is a rate of $_<br> per hamburger
ipn [44]
ANSWER: $4 per hamburger
3 0
3 years ago
Read 2 more answers
If k is an integer, what is <br> k + 1<br> /2<br> !<br> ? Why?
Amanda [17]

If k\in\mathbb{Z} than k+1\in\mathbb{Z} however any \mathbb{Z} divided by 2 is in \mathbb{Q}.

But it is not so simple.

If k is odd then k+1 is even but when even number is divided by 2, you get an odd number which is in \mathbb{Z}.

However if k is even then k+1 is odd and when we divide that by 2, you get a number like for example \frac{5}{2} which is not in \mathbb{Z} but rather inside \mathbb{Q}. There are fortunately no irrational numbers.

There is also a problem with zero, zero is neither odd nor even but still an integer. If your k happens to be -1, k+1=0, and zero divided by 2 is still just 0 which is in \mathbb{Z}.

So to sum up,

If k is odd and not -1, then \frac{k+1}{2}\in\mathbb{Z}.

Or to put it in math \forall k\in\mathrm{odd}-\{-1\}\cup\{0\}\implies\frac{k+1}{2}\in\mathbb{Z}.

If k is even or -1, then \frac{k+1}{2}\in\mathbb{Q}.

Or to put it in math \forall k\in\mathrm{even}\cup \{-1\}\implies\frac{k+1}{2}\in\mathbb{Q}.

<u>Notes</u>:

\mathbb{Z} is a set of integers.

\mathbb{Q} is a set of rational numbers.

\mathbb{Z}\subset\mathbb{Q} means integers are a subset of rational numbers, that is, every integer is a also a fraction, however not every fraction is an integer.

Hope this helps :)

8 0
3 years ago
Create an equation using the table of values below.
djyliett [7]

Answer:

1.  y = 2x - 1

Step-by-step explanation:

See attached image.

7 0
2 years ago
Other questions:
  • Mr. Richard owns an orchard that has a rectagular fence . The orchard is 36 yards long and 18 yards wide . if he walks across th
    8·1 answer
  • Anne Katz, the owner of Katz Sport Shop, lends $8,000 to Shelley Slater to help her open an art shop. Shelley plans to repay Ann
    12·2 answers
  • Is 0.33333333333333333333333333333333333333.............. a rational number?
    8·1 answer
  • Need this answered ASAP!
    11·1 answer
  • What is the value of x in the equation 3x – y = 18, when y = 27?
    14·2 answers
  • Determine the models that could represent a compound interest account that is growing exponentially.
    7·1 answer
  • Please please help me with those questions
    5·1 answer
  • I just put a 100 point question and offered to mark brainliest no one anwser me
    15·2 answers
  • R= 4/3(p-q) <br><br>solve for p ​
    11·1 answer
  • Determine whether the sequence converges or diverges. if it converges, find the limit. (if an answer does not exist, enter dne.
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!