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kondaur [170]
3 years ago
7

May i have 5 over 8 as a decimal form

Mathematics
1 answer:
stich3 [128]3 years ago
6 0
5/8 is just 5 divided by 8. The answer is 0.625. 
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Solve the following equation for D. Be sure to take into account whether a letter is capitalized or not. fD - 7 = q^2
Alecsey [184]

Answer:

\displaystyle D=\frac{q^2+7}{f}

Step-by-step explanation:

<u>Equation Solving</u>

We are given the equation:

fD - 7 = q^2

It's required to solve the equation for D. All letters must preserve their capitalization.

We must isolate the letter D by removing from the left side all the terms and coefficients that surround it.

Adding 7:

fD = q^2+7

Dividing by f:

\mathbf{\displaystyle D=\frac{q^2+7}{f}}

5 0
3 years ago
Please Hurry! I will award the first person right the brainlyest award
Len [333]

Answer:

y = -3

Step-by-step explanation:

When you graph it on a graphing calculator or on desmos, it appears to be at y = -3

6 0
2 years ago
Read 2 more answers
If a pair of shoes cost $40 and they are on sale for 30% off how much would they be
yulyashka [42]

multiply 40 by 30% to find the discount then subtract

40 * 0.30 = 12

40-12 = 28

they would cost $28

6 0
3 years ago
Write an equation of a line that is perpendicular to the line y=2/3x and passes through origin
sesenic [268]

keeping in mind that perpendicular lines have negative reciprocal slopes, hmmm what's the slope of the equation above anyway?

\bf y = \cfrac{2}{3}x\implies y = \stackrel{\stackrel{m}{\downarrow }}{\cfrac{2}{3}}x+0\qquad \impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array} \\\\[-0.35em] ~\dotfill

\bf \stackrel{\textit{perpendicular lines have \underline{negative reciprocal} slopes}} {\stackrel{slope}{\cfrac{2}{3}}\qquad \qquad \qquad \stackrel{reciprocal}{\cfrac{3}{2}}\qquad \stackrel{negative~reciprocal}{-\cfrac{3}{2}}}

so we're really looking for the equation of a line whose slope is -3/2 and runs through (0,0).

\bf (\stackrel{x_1}{0}~,~\stackrel{y_1}{0})~\hspace{10em} \stackrel{slope}{m}\implies -\cfrac{3}{2} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{0}=\stackrel{m}{-\cfrac{3}{2}}(x-\stackrel{x_1}{0})\implies y=-\cfrac{3}{2}x

7 0
3 years ago
How to do this problem?
Anvisha [2.4K]
The measurement are the same. From 2,4,6,8. After you known those equal to 103. You know a line equals 180. So you would do 180-103=77. So from 1,3,5,7 will all be 77 degree.
5 0
3 years ago
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