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3 years ago

100 POINTS PLEASE PROVIDE STEPS FIND FIRST DERIVATIVE AND SIMPLIFY ANSWER

Mathematics

2 answers:

BaLLatris [955]3 years ago

5 0

Answer:

h'(x) = (-x² ln x + x² + 1) / (x (x² + 1)^(³/₂))

Step-by-step explanation:

h(x) = ln x / √(x² + 1)

You can either use quotient rule, or you can rewrite using negative exponents and use product rule.

h(x) = (ln x) (x² + 1)^(-½)

h'(x) = (ln x) (-½) (x² + 1)^(-³/₂) (2x) + (1/x) (x² + 1)^(-½)

h'(x) = (-x ln x) (x² + 1)^(-³/₂) + (1/x) (x² + 1)^(-½)

h'(x) = (x² + 1)^(-³/₂) (-x ln x + (1/x) (x² + 1))

h'(x) = (1/x) (x² + 1)^(-³/₂) (-x² ln x + x² + 1)

h'(x) = (-x² ln x + x² + 1) / (x (x² + 1)^(³/₂))

dimaraw [331]3 years ago

3 0

Solution:

h(x) = ln(x)/√x^2+1

h(x) = ln(x) * (x^2 + 1)^-1/2

h(x) = ln(x) * (-1/2) * (x^2 + 1)^-3/2 * 2x + 1/x * (x^2 + 1)^-1/2

h(x) = -x ln(x) * (x^2 + 1)^-3/2 + 1/x * (x^2 + 1)^-1/2

h(x) = (x^2 + 1)^-3/2 * (-x ln(x) + 1/x * (x^2 + 1))

h(x) = -x^2ln(x)+x^2+1/(x(x^2+1)^3/2)

Best of Luck!

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2 years ago

Find the 76th term of the arithmetic sequence 17, 19, 21, ...

Dominik [7]

Answer: 167

Step-by-step explanation: To find the 76th term of this arithmetic sequence, we will be using our explicit formula which is shown below.

$^{a}n = ^{a}1 (n - 1)d$

Since we want to determine the 76th term, we are going

to substitute 76 in for <em>n</em> in our explicit formula.

Then, $^{a}1$ will be our first term in our sequence which is 17.

Lastly, <em>d</em> is our common difference or the difference between each of the terms in our arithmetic sequence which is 2.

So we have $^{a} 76 = 17 + (76 - 1)(2)$ .

Now we have all the information we need. Just simplify from here.

Make sure to apply order of operations because this is where many

students make mistakes. Inside the parentheses first!

(76 - 1) is going to be 75.

So we have $^{a} 76 = 17 + (75)(2)$ .

Then, we have to make sure we multiply before we add.

So (75)(2) is going to give us 150.

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3 years ago

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Delicious77 [7]

Answer:

$P(X \geq 6) = P(X=6) +P(X=7) +P(X=8) +P(X=9) +P(X=10)$

And using the probability mass function we got:

$P(X=6)=(10C6)(0.5)^6 (1-0.5)^{10-6}=0.205$

$P(X=7)=(10C7)(0.5)^7 (1-0.5)^{10-7}=0.117$

$P(X=8)=(10C8)(0.5)^8 (1-0.5)^{10-8}=0.0439$

$P(X=9)=(10C9)(0.5)^9 (1-0.5)^{10-9}=0.0098$

$P(X=10)=(10C10)(0.5)^{10} (1-0.5)^{10-10}=0.000977$

And adding the values we got:

$P(X\geq 6) = 0.377$

The best answer would be:

D. 0.377

Step-by-step explanation:

Let X the random variable of interest, on this case we now that:

$X \sim Binom(n=10, p=0.5)$

The probability mass function for the Binomial distribution is given as:

$P(X)=(nCx)(p)^x (1-p)^{n-x}$

Where (nCx) means combinatory and it's given by this formula:

$nCx=\frac{n!}{(n-x)! x!}$

For this case in order to pass he needs to answer at leat 6 questions and we can rewrite this:

$P(X \geq 6) = P(X=6) +P(X=7) +P(X=8) +P(X=9) +P(X=10)$

And using the probability mass function we got:

$P(X=6)=(10C6)(0.5)^6 (1-0.5)^{10-6}=0.205$

$P(X=7)=(10C7)(0.5)^7 (1-0.5)^{10-7}=0.117$

$P(X=8)=(10C8)(0.5)^8 (1-0.5)^{10-8}=0.0439$

$P(X=9)=(10C9)(0.5)^9 (1-0.5)^{10-9}=0.0098$

$P(X=10)=(10C10)(0.5)^{10} (1-0.5)^{10-10}=0.000977$

And adding the values we got:

$P(X\geq 6) = 0.377$

The best answer would be:

D. 0.377

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3 years ago