Use common denominators to write an equivalent fraction for each fraction please help I will say thanks

The delivery times for all food orders at a fast-food restaurant during the lunch hour are normally distributed with a mean of m

UkoKoshka [18]

Answer:

Let X the random variable that represent the delivery times of a population, and for this case we know the distribution for X is given by:

$X \sim N(14.7,3.7)$

Where $\mu=14.7$ and $\sigma=3.7$

Since the distribution of X is normal then we know that the distribution for the sample mean $\bar X$ is given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

And we have;

$\mu_{\bar X}= 14.70$

$\sigma_{\bar X} =\frac{3.7}{\sqrt{40}}= 0.59$

Step-by-step explanation:

Assuming this question: The delivery times for all food orders at a fast-food restaurant during the lunch hour are normally distributed with a mean of 14.7 minutes and a standard deviation of 3.7 minutes. Let R be the mean delivery time for a random sample of 40 orders at this restaurant. Calculate the mean and standard deviation of $\bar X$ Round your answers to two decimal places.

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Solution to the problem

Let X the random variable that represent the delivery times of a population, and for this case we know the distribution for X is given by:

$X \sim N(14.7,3.7)$

Where $\mu=14.7$ and $\sigma=3.7$

Since the distribution of X is normal then we know that the distribution for the sample mean $\bar X$ is given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

And we have;

$\mu_{\bar X}= 14.70$

$\sigma_{\bar X} =\frac{3.7}{\sqrt{40}}= 0.59$

4 0

3 years ago

On a certain hot summer's day, 645 people used the public swimming pool. The daily prices are $1.75 for children and $2.50 for

VladimirAG [237]

Answer:

327 children and 318 adults

Step-by-step explanation:

The x be the amount of children and y be the amount of adults that were at the swimming pool. We can use this to set up a system of equations:

x+y=645

1.75x+2.50y=1367.25

Move y to the other side in the first equation to isolate x and solve the system using substitution:

x=645-y

1.75(645-y)+2.50y=1367.25

Distribute

1128.75-1.75y+2.50y=1367.25

1128.75+0.75y=1367.25

Subtract 1128.75 from both sides

0.75y=238.5

Divide both sides by 0.75

y=318

x=645-y

x=645-318

x=327

327 children and 318 adults swam at the pool that day

4 0

2 years ago

A pencil factory makes 50 cases of pencils in 5 hours.

Oduvanchick [21]

If a pencil factory makes 50 cases of pencils in 5 hours. Let's first find out how many cases are made per hour.

50 ÷ 5 = 10 cases per hour

Now you need to know how long it will take to make 55 cases. Since we already know that it takes 5 hours to make 50 cases. So you need to know how many cases for the extra 5 cases. If it takes 1 hour to make 10 cases, it would only take 1/2 hour to make 5 cases.

So it would take 5 1/2 hours to make 55 cases.

Hope this helps. :)

5 0

3 years ago

How many integers between 10000 and 99999, inclusive, are divisible by 3 or<br> 5 or 7?

Yuki888 [10]

Answer: Hence, there are approximately 48884 integers are divisible by 3 or 5 or 7.

Step-by-step explanation:

Since we have given that

Integers between 10000 and 99999 = 99999-10000+1=90000

n( divisible by 3) = $\dfrac{90000}{3}=30000$