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fomenos
2 years ago
10

You throw a dart at the board shown. Your dart is equally likely to hit any point inside the square board. Find the probability

that you do not get 10 points. Write your answer as a decimal rounded to the nearest thousandth.

Mathematics
1 answer:
KiRa [710]2 years ago
7 0

The board that makes the question complete is attached with this answer.

Answer:

The probability that you do not get 10 points is 0.913 (To the nearest thousandths).

Step-by-step explanation:

Given that your dart is equally likely to hit any point inside the square board, we are required to find the probability that you do not get 10 points.

This can be obtained by first obtaining the probability of you getting 10 points, and then subtracting it from 1.

The Probability of Success plus The Probability of Failure of an event is always equal to 1.

Let p be the probability of success, and q be the probability of failure. Then

p + q = 1

=> p = 1 - q

And q = 1 - p

From the attached image, we need to find the area of the entire board, and the area of the circle that contains 10.

Area of entire board = 18² = 324

Area of the circle containing 10 = πr² = π(3²) = 9π

Where r is the radius, 3in.

Probability of hitting 10, P(10) = 9π/324

= 0.08727

≈ 0.087 (to the nearest thousandths)

Now, the probability of not hitting 10

= 1 minus probability of hitting 10.

= 1 - 0.087

= 0.913

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Read 2 more answers
I don't know how to do this or what i'm doing plz help
mote1985 [20]

recalling that d = rt, distance = rate * time.


we know Hector is going at 12 mph, and he has already covered 18 miles, how long has he been biking already?


\bf \begin{array}{ccll} miles&hours\\ \cline{1-2} 12&1\\ 18&x \end{array}\implies \cfrac{12}{18}=\cfrac{1}{x}\implies 12x=18\implies x=\cfrac{18}{12}\implies x=\cfrac{3}{2}


so Hector has been biking for those 18 miles for 3/2 of an hour, namely and hour and a half already.

then Wanda kicks in, rolling like a lightning at 16mph.

let's say the "meet" at the same distance "d" at "t" hours after Wanda entered, so that means that Wanda has been traveling for "t" hours, but Hector has been traveling for "t + (3/2)" because he had been biking before Wanda.

the distance both have travelled is the same "d" miles, reason why they "meet", same distance.


\bf \begin{array}{lcccl} &\stackrel{miles}{distance}&\stackrel{mph}{rate}&\stackrel{hours}{time}\\ \cline{2-4}&\\ Hector&d&12&t+\frac{3}{2}\\[1em] Wanda&d&16&t \end{array}\qquad \implies \begin{cases} \boxed{d}=(12)\left( t+\frac{3}{2} \right)\\[1em] d=(16)(t) \end{cases}


\bf \stackrel{\textit{substituting \underline{d} in the 2nd equation}}{\boxed{(12)\left( t+\frac{3}{2} \right)}=16t}\implies 12t+18=16t \\\\\\ 18=4t\implies \cfrac{18}{4}=t\implies \cfrac{9}{2}=t\implies \stackrel{\textit{four and a half hours}}{4\frac{1}{2}=t}

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