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Alinara [238K]
3 years ago
12

Which is a benefit of peer-to-peer networking?

Computers and Technology
1 answer:
RUDIKE [14]3 years ago
5 0

Answer:

Easy file sharing: An advanced P2P network can share files quickly over large distances. Reduced costs: There is no need to invest in a separate computer for a server when setting up a P2P network. Adaptability: P2P network extends to include new clients easily.

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What is the difference between websites and web page​
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webpage is a single document on internet under a unique URL. Website is a collection of multiple webpages in which information on related topics or subject is linked together.

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3 years ago
Como puedo poner fondo a mi teclado​
nikdorinn [45]

CAN YOU TRANSLATE IT TO ENGLISH PLEASE SO I CAN AWANSER

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3 years ago
You have a shared folder named Reports. Members of the Managers group have been given Write access to the shared folder. Mark Ma
Anna71 [15]

Answer:

Following are the solution to the given question:

Explanation:

The common folder called Report has also been shared. Writing access to a shared folder was given to management group members. Mark is a member of a group of managers. We can access the files within your reporting directory, but you really should not access the Confidential.xls file. We want to add Mark Mangum to our ACL files using Deny permissions on Confidential.xls.

5 0
3 years ago
For angular how can we set up th edatabse.
lesya [120]
You can not communicate directly between Angular and MySQL. You'll need to build a back-end Web service that calls MySql using php or node. Angular can communicate with this back-end Web service via http.
8 0
3 years ago
Def build_dictionary(string):
MissTica

Answer:

Follows are the code to this question:

def build_word_counter(string):#defining a method build_word_counter that accepts string as a parameter  

   d = dict()#defining d variable as a dictionary

   for x in string:#defining for loop that use string

       x = x.lower()#Use lower method  

       if not d.get(x):#defining if block that holds value in d variable

           d[x] = 1#use dictionary to hold value in 1

       else:#defining else block

           d[x] += 1#use dictionary to increment value by 1

   return d#return dictionary

print(build_word_counter(["Like","like","LIKE"]))#use print method to call method

def build_letter_distribution(string):#defining a method build_letter_distribution that accepts string variable

   d = dict()#defining d variable as a dictionary

   for i in string:#defining for loop to count string value

       for j in i:#defining for loop to hold string as number

           if not d.get(j):#defining if block that doesn't get value in dictionary  

               d[j] = 1#hold value in dictionary  

           else:#defining else block

               d[j] += 1#use dictionary to increment the dictionary value

   return d#return dictionary

print(build_letter_distribution(["Like","test","abcdEFG"]))#use print method to return its value

Output:

please find the attached file.

Explanation:

In the first program a method, "build_word_counter" is defined that accepts a string variable in its parameter, and inside the method, a dictionary variable "d" is defined that uses the for loop to hold string value and convert all value into lower case.

In the next step, a conditional statement is used that holds value in the dictionary and count its word value.

In the second program a method, "build_letter_distribution" is defined that holds string variable in its parameter, and inside the method, a dictionary variable "d" is defined that uses the two for loop and in if the block, it holds value in the dictionary and returns its value, and use print method to print its return its value.

4 0
3 years ago
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