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Nina [5.8K]
2 years ago
13

What about the inequality sign like < = >

Mathematics
1 answer:
docker41 [41]2 years ago
4 0
The < and > signs mean lesser and greater than. = means equal(s). The signs will always look like they are eating the bigger value. For example:
12<29
Twelve is lesser than twenty-nine, or
29>12
Twenty-nine is greater than twelve.
An equation uses an equal sign
12+8=20
When you're using all of them, it can look like this:
1<n<29
This is read as "one is lesser than n which is lesser than 29". These can be used to determine the lengths of the sides of a triangle. In this case, n must be between 1 and 29 for it to be the side of a triangle.
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Select the graph that does not represent two quantities in a proportional relationship.
Lerok [7]
The answer is b since it does not touch the origin! (0,0)
5 0
2 years ago
A certain dodgeball court is a circle with a square perfectly inscribed inside it. the square represents the playing field, whil
cluponka [151]
<span>Exactly 8*pi - 16
 Approximately 9.132741229 For this problem, we need to subtract the area of the square from the area of the circle. In order to get the area of the circle, we need to calculate its radius, which will be half of its diameter. And the diameter will be the length of the diagonal for the square. And since the area of the square is 16, that means that each side has a length of 4. And the Pythagorean theorem will allow us to easily calculate the diagonal. So: sqrt(4^2 + 4^2) = sqrt(16 + 16) = sqrt(32) = 4*sqrt(2) Therefore the radius of the circle is 2*sqrt(2). And the area of the circle is pi*r^2 = pi*(2*sqrt(2)) = pi*8 So the area of the rest areas is exactly 8*pi - 16, or approximately 9.132741229</span>
6 0
2 years ago
The hypotenuse of a right triangle measures 58 cm and one of its legs measures 42 cm. What is the length of the missing leg? 10
Nutka1998 [239]
If the hypotenuse is 58cm, and one of the others legs is 42cm the answer would be 40cm

Explanation:

Here you have to use the formula

{a}^{2} + {b}^{2} = {c}^{2}
Then you have to pose the formula in terms of one of the legs, so:

{a}^{2} = {c}^{2} - {b}^{2}
a = \sqrt{ {c}^{2} - {b}^{2}}
So when you change the letter for numbers you have that:

a = \sqrt{ {58}^{2} - {42}^{2} }

a=40
5 0
2 years ago
Hi i just need help checking if my answer is correct I have been working on a implicit diffrention problem and I need some help.
SSSSS [86.1K]

Answer:

  \dfrac{dy}{dx}=\dfrac{-4x^3y+2y^3+3x^2y^3}{x^4-6xy^2-3x^3y^2}

Step-by-step explanation:

Normally, when I do this, I differentiate each term first with respect to x then with respect to y. In this solution, I differentiated the entire expression with respect to x, then with respect to y. That makes separating the dx and dy coefficients much easier, so the solution almost falls into your lap.

  -x^4 y + 2 x y^3 + x^3 y^3=0 \qquad\text{given}\\\\(-4x^3y+2y^3+3x^2y^3)dx+(-x^4+6xy^2+3x^3y^2)dy=0\\\\(-4x^3y+2y^3+3x^2y^3)dx=(x^4-6xy^2-3x^3y^2)dy\\\\\boxed{\dfrac{dy}{dx}=\dfrac{-4x^3y+2y^3+3x^2y^3}{x^4-6xy^2-3x^3y^2}}

6 0
2 years ago
How do i do this......
andrew11 [14]

Answer:

b is correct answer

Step-by-step explanation:

hope it helped

5 0
3 years ago
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