Answer:
1. A container of milk 2L
2. An Eyedropper has 1 mL
3. A cup of punch 250 mL
4. A jar of pickles 500mL
Step-by-step explanation:
Without even measuring, just think of this problem logically. Remember that a 1 L is 1000mL, so it is 1000 times more than 1 mL.
A milk container would hold more than a cup of milk and that is more than 20 mL. The most logical answer would be 2L.
An eyedropper can hold just a little amount of liquid. Just think that it dispenses liquid in drops, the best answer would be 1mL (which is actually an estimate of the volume of a drop is.)
A cup of punch is about 250 mL. The keyword there is a CUP and 25L is a big amount and the cup would have to be HUGE.
Same as above, the keyword there is a jar. A 50L jar would be a very big amount for just a jar of pickles.
Answer:
A. Y-68=-5(x-14)
Step-by-step explanation:
Mary is spending money at the average rate of $5 per day. After 14 days she has $68 left. The amount left depends on the number of days that have passed. write an equation for the situation
We find the equation using the point slope equation of a line. This is given as:
y - y1 = m(x-x1)
The slope intercept form will be
y = -5x + b
since the amount decreases by $5 per day...
Our slope is -5 so m=-5
We have a point (x1,y1) = (14, 68)
Hence, we have:
y-68 = -5(x-14)
Option A is correct
The equation would be -5+(-12), so the answer would be -17 :)
Your answer should be B. 58.08 PI m3
Answer:
Step-by-step explanation:
To write the expression as a single logarithm, or condense it, use the properties of logarithms.
1) The power property of logarithms states that 
. In other words, the exponent within a logarithm can be brought out in front so it's multiplied by the logarithm. This means that the number in front of the logarithm can also be brought inside the logarithm as an exponent.
So, in this case, we can move the 3 and the 4 inside the logarithms as exponents. Apply this property as seen below:
2) The product property of logarithms states that 
. In other words, the logarithm of a product is equal to the sum of the logarithms of its factors. So, in this case, write the expression as a single logarithm by taking the log (keep the same base) of the product of 
and 
. Apply the property as seen below and find the final answer.
So, the answer is .
