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3 years ago

Name the algebraic property demonstrated in the example below: (1 point) x ⋅ y ⋅ z = y ⋅ x ⋅ z

Mathematics

1 answer:

trapecia [35]3 years ago

7 0

Reorganisation of the equation? I don't know what you call it but it's what I was taught

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Stan's cookie recipe makes 24 cookies and calls for exactly 384 sprinkles. He is wondering how many sprinkles (p)eft parenthesis

OLEGan [10]

Answer:

960 sprinkles

Step-by-step explanation:

x = sprinkles

For this problem we will create a ratio

$\frac{24}{384} :\frac{60}{x}$

24x=384*60

24x=23,040

x=23,040/24

x=960

Stan would need 960 sprinkles!

Hope this helps!

(pls mark as brainiest)

Thanks!

5 0

3 years ago

Read 2 more answers

The table above gives values of the differentiable functions f and g, and f', the derivative of f, at selected values of x. If g

Aleks [24]

Answer:

Step-by-step explanation:

i just need points

7 0

2 years ago

How many solutions does the system of equations have? 4x= -12y +16 and x+3y=4

Verdich [7]

Answer:

x=4-3y

Step-by-step explanation:

7 0

3 years ago

An article contained the following observations on degree of polymerization for paper specimens for which viscosity times concen

devlian [24]

Answer:

(a) A 95% confidence interval for the population mean is [433.36 , 448.64].

(b) A 95% upper confidence bound for the population mean is 448.64.

Step-by-step explanation:

We are given that article contained the following observations on degrees of polymerization for paper specimens for which viscosity times concentration fell in a certain middle range:

420, 425, 427, 427, 432, 433, 434, 437, 439, 446, 447, 448, 453, 454, 465, 469.

Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;

P.Q. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean = $\frac{\sum X}{n}$ = 441

s = sample standard deviation = $\sqrt{\frac{\sum (X-\bar X)^{2} }{n-1} }$ = 14.34

n = sample size = 16

$\mu$ = population mean

Here for constructing a 95% confidence interval we have used One-sample t-test statistics as we don't know about population standard deviation.

So, 95% confidence interval for the population mean, $\mu$ is ;

P(-2.131 < $t_1_5$ < 2.131) = 0.95 {As the critical value of t at 15 degrees of

freedom are -2.131 & 2.131 with P = 2.5%}

P(-2.131 < $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ < 2.131) = 0.95

P( $-2.131 \times {\frac{s}{\sqrt{n} } }$ < ${\bar X-\mu}$ < $2.131 \times {\frac{s}{\sqrt{n} } }$ ) = 0.95

P( $\bar X-2.131 \times {\frac{s}{\sqrt{n} } }$ < $\mu$ < $\bar X+2.131 \times {\frac{s}{\sqrt{n} } }$ ) = 0.95

95% confidence interval for $\mu$ = [ $\bar X -2.131 \times {\frac{s}{\sqrt{n} } }$ , $\bar X +2.131 \times {\frac{s}{\sqrt{n} } }$ ]

= [ $441-2.131 \times {\frac{14.34}{\sqrt{16} } }$ , $441+2.131 \times {\frac{14.34}{\sqrt{16} } }$ ]

= [433.36 , 448.64]

(a) Therefore, a 95% confidence interval for the population mean is [433.36 , 448.64].

The interpretation of the above interval is that we are 95% confident that the population mean will lie between 433.36 and 448.64.

(b) A 95% upper confidence bound for the population mean is 448.64 which means that we are 95% confident that the population mean will not be more than 448.64.

6 0

3 years ago

X+10=1/3(5x+10) How do you solve this equation?

Nikitich [7]

Answer:

x = 10

Step-by-step explanation:

First, subtract 10 from both sides

Next, Simplify

Then, subtract 5/3x from both sides

After, simplify

Lastly, multiply both sides by 3

Then finally simplify for your final answer of x = 10

Hope this helps! :)

3 0

2 years ago

Read 2 more answers