I will use 0b to refer to binary numbers: ex: 0b1 = 1, 0b10 = 2
0b100 = 4 and 0b11 = 3
4+3 = 7
convert 7 to binary and you get 111.
Hope this helps, and May the Force Be With You!
<span>-Jabba</span>
In a block in a blockchain, a resource which represent the transactional data, sender, receiver, and number of coins is: A. data.
<h3>What is a blockchain?</h3>
A blockchain can be defined as a digital and dynamic financial system that is designed and developed to be used in recording and maintaining transactions that are associated with or made through the use of a bitcoin, usually as a database containing various set of data.
In this context, we can infer and logically deduce that data is a resource that typically represent all of the transactional data, sender, recipient (receiver), and the number of bitcoins in a block in a blockchain.
Read more on blockchain here: brainly.com/question/25700270
#SPJ1
Based on my personal experience in the workforce, all of the above would be the correct answer. That's based off my experience though. Owners would regularly come in and talk to our managers and employees to make sure everything was kept in order and in compliance. The only other answer I could see fit would be supervisors. Hope I was able to help :)
Answer:
1 Array languages
2 Assembly languages
3 Authoring languages
4 Constraint programming languages
5 Command line interface languages
6 Compiled languages
7 Concurrent languages
8 Curly-bracket languages
9 Dataflow languages
10 Data-oriented languages
11 Decision table languages
12 Declarative languages
13 Embeddable languages
13.1 In source code
13.1.1 Server side
13.1.2 Client side
13.2 In object code
14 Educational languages
15 Esoteric languages
16 Extension languages
17 Fourth-generation languages
18 Functional languages
18.1 Pure
18.2 Impure
19 Hardware description languages
19.1 HDLs for analog circuit design
19.2 HDLs for digital circuit design
20 Imperative languages
21 Interactive mode languages
22 Interpreted languages
23 Iterative languages
Explanation:
Answer:
e(a) = 0
e(b) = 10
e(c) = 110
e(d) = 1110
Explanation:
The Worst case will happen when f(a) > 2*f(b) ; f(b) > 2*f(c) ; f(c) > 2*f(d) ; f(d) > 2*f(e) and f(e) > 2*f(f).
Where f(x) is frequency of character x.
Lets consider the scenario when
f(a) = 0.555, f(b) = 0.25, f(c) = 0.12, f(d) = 0.05, f(e) = 0.02 and f(f) = 0.005
Please see attachment for image showing the steps of construction of Huffman tree:- see attachment
From the Huffman tree created, we can see that endcoding e() of each character are as follows:-
e(a) = 0
e(b) = 10
e(c) = 110
e(d) = 1110
e(e) = 11110
e(f) = 11111
So we can see that maximum length of encoding is 5 in this case.
