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sergeinik [125]
3 years ago
14

Many Web browsers allow users to open anonymous windows. During a browsing session in an anonymous window, the browser does not

record a browsing history or a list of downloaded files. When the anonymous window is exited, cookies created during the session are deleted. Which of the following statements about browsing sessions in an anonymous window is true
Computers and Technology
1 answer:
Nataly_w [17]3 years ago
3 0

Answer:

This question was initially incomplete. Here is the full question:

Many Web browsers allow users to open anonymous windows. During a browsing session in an anonymous window, the browser does not record a browsing history or a list of downloaded files. When the anonymous window is exited, cookies created during the session are deleted. Which of the following statements about browsing sessions in an anonymous window is true?

a) The activities of a user browsing in an anonymous window will not be visible to people who monitor the user's network, such as the system administrator.

b) Items placed in a Web store's shopping cart for future purchase during the anonymous browsing session will not be saved on the user's computer.

c) A user will not be able to log in to e-mail or social media accounts during the anonymous browsing session.

d) A user browsing in an anonymous window will be protected from viruses launched from any Web sites visited or files downloaded.

The correct answer is b) Items placed in a Web store's shopping cart for future purchase during the anonymous browsing session will not be saved on the user's computer.

Explanation:

For e-commerce sites, shopping cart information are stored as cookies on the visitor's computer such that when the website visitor leaves the website and comes back a few days later, their shopping preferences are remembered.

If the website visitor uses an anonymous window, the cookies created during the browsing session will be deleted when the anonymous website is exited and so, items placed in the shopping cart for future purchase will not be saved.

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I am having trouble with this python question. I am in a beginner level class also so any solution that isn't too complex would
Delicious77 [7]

The code:

filename = input("> ")

with open(filename, "r") as file:

   items = file.read()

   items = items.split("\n")

   for index, item in enumerate(items):

       items[index] = item.split("\t")

   for item in items:

       if item[3] == "Available":

           print(f"{item[1]} ({item[0]}) -- {item[2]}")

Explenation:

1. We make the user enter the file's path, in our case "food.txt". This does only work if the .txt file is in the <u>same</u> directory as our code.

2. We get the content of our .txt file with the "open" function. If we use the "open" function inside of a "with" statement we don't have to deal with closing the file after we opened it. The file will close as soon as we exit the statement. The argument "r" indicates that we only want to read the file, not do anything else with it.

3. However the variable "file" doesn't contain the <u>contents</u> of "food.txt", only the class object of our file (if you try "print(file)" you'll only get nonsense). We can simply get the content of the file by calling ".read()" after.

4. We can separate this long str using the ".split()" function. The split function seperates a string by another sertain string (in our case "\n", since the different items are seperated by a newline). Now "items" is a list of strings.

5. Next we go through all items in "items" and separate them by "\t", again using the ".split()" function. Enumerate makes a list of indexes and values from another list (in our case, "items").

6. Now we have a list of lists of strings. The only thing left to do is go through every item and print it if the item's third item is equal to "Available" (notice that this is case-sensative). And print out the result in the desired format.

The code works for me, please ask me if there is anything you don't understand (or if the code is incorrect). Happy to help :D

5 0
2 years ago
5.17 (Calculating Sales) An online retailer sells five products whose retail prices are as follows: Product 1, $2.98; product 2,
Dima020 [189]

Answer:

import java.util.Scanner;

public class Main

{

public static void main(String[] args) {

   

    //Initialize the prices as constants

    final double PRODUCT_1_PRICE = 2.98;

    final double PRODUCT_2_PRICE = 4.50;

    final double PRODUCT_3_PRICE = 9.98;

    final double PRODUCT_4_PRICE = 4.49;

    final double PRODUCT_5_PRICE = 6.87;

   

    //Declare the other variables

    int productNumber, quantitySold;

    double total = 0.0;

   

    //Create a Scanner object to get input

    Scanner input = new Scanner(System.in);

   

    //Create a while loop

    while(true){

        //Ask the user to enter the productNumber

     System.out.print("Enter the product number or 999 to quit: ");

     productNumber = input.nextInt();

     

     // Stop the loop, if productNumber is 999(sentinel value, you may choose any value you want)

     if(productNumber == 999)

         break;

     

     //Ask the user to enter the quantitySold

     System.out.print("Enter the quantity sold: ");

     quantitySold = input.nextInt();

     

     //Create a switch statement that works depending on the productNumber entered.

     //For example, if the productNumber is 1, it multiplies the quantitySold by PRODUCT_1_PRICE

     //   and adds the result to the total. If productNumber is 2, it does the same for product 2 ...

     switch(productNumber){

         case 1:

             total += quantitySold * PRODUCT_1_PRICE;

             break;

         case 2:

             total += quantitySold * PRODUCT_2_PRICE;

             break;

         case 3:

             total += quantitySold * PRODUCT_3_PRICE;

             break;

         case 4:

             total += quantitySold * PRODUCT_4_PRICE;

             break;

         case 5:

             total += quantitySold * PRODUCT_5_PRICE;

             break;

     }

    }

 

 //Print the total (when the loop is done)

 System.out.println("The total is $" + total);

}

}

Explanation:

*The code is in Java.

You may see the explanation as comments in the code.

4 0
3 years ago
Write pseudo code that performs the following: Ask a user to enter a number. If the
CaHeK987 [17]
Answer:
BEGIN
INPUT N
IF N>0 AND N<10 THEN
OUTPUT "blue"
ELSE
IF N>10 AND N<20 THEN
OUTPUT "red"
ELSE
IF N>20 AND N<30 THEN
OUTPUT "green"
ELSE
OUTPUT "It is not a correct color option"
ENDIF
END.

Explanation:

3 0
2 years ago
Write a program that will predict the size of a population of organisms. The program should ask the user for the starting number
sineoko [7]

Answer:

// using c++ language

#include "stdafx.h";

#include <iostream>

#include<cmath>

using namespace std;

//start

int main()

{

 //Declaration of variables in the program

 double start_organisms;

 double daily_increase;

 int days;

 double updated_organisms;

 //The user enters the number of organisms as desired

 cout << "Enter the starting number of organisms: ";

 cin >> start_organisms;

 //Validating input data

 while (start_organisms < 2)

 {

     cout << "The starting number of organisms must be at least 2.\n";

     cout << "Enter the starting number of organisms: ";

     cin >> start_organisms;

 }

 //The user enters daily input, here's where we apply the 5.2% given in question

 cout << "Enter the daily population increase: ";

 cin>> daily_increase;

 //Validating the increase

 while (daily_increase < 0)

 {

     cout << "The average daily population increase must be a positive value.\n ";

     cout << "Enter the daily population increase: ";

     cin >> daily_increase;

 }

 //The user enters number of days

 cout << "Enter the number of days: ";

 cin >> days;

 //Validating the number of days

 while (days<1)

 {

     cout << "The number of days must be at least 1.\n";

     cout << "Enter the number of days: ";

     cin >> days;

 }

 

 //Final calculation and display of results based on formulas

 for (int i = 0; i < days; i++)

 {

     updated_organisms = start_organisms + (daily_increase*start_organisms);

     cout << "On day " << i + 1 << " the population size was " << round(updated_organisms)<<"."<<"\n";

     

     start_organisms = updated_organisms;

 }

 system("pause");

  return 0;

//end

}

Explanation:

6 0
3 years ago
Can you give me a long list of kid's cartoons
Delicious77 [7]
SpongeBob, Teen Titan Go, Future Worm. That's all I can think!
8 0
2 years ago
Read 2 more answers
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