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slavikrds [6]
3 years ago
10

In a rectangle the length is 6 more than twice the width, if the perimeter is 60 inches, what is the width of the rectangle

Mathematics
1 answer:
Vitek1552 [10]3 years ago
7 0
Length(l)= 2w+6
width(w)= w

Perimeter(P)= 60 inches= 2w+2l (divide each side by 2 to simplify)
P=30 in= w+l

Plug in expression for "l" to be able to add like terms.
P=30=w+l
P=30=w+(2w+6)
P= 30= 3w+6
P= 24= 3w
w= 8 inches

Answer: 
The width of the rectangle is 8 inches.

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vekshin1
<h3>Answer: Choice C</h3>

{x | x < -12 or x > -6}

=========================================================

Explanation:

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The inequality sign flips when we divide both sides by a negative value.

Let's do the same for the second inequality.

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Side note: The intervals x < -12 and x > -6 do not overlap in any way. There's a gap between the two pieces. We consider these intervals to be disjoint. The number line graph is below.

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