Recall that an equation in slope-intercept form is as follows:
where m is the slope of the line, and (0,b) is the y-intercept.
Substituting m=-6, and b=-1/2 we get:
Simplifying the above result we get:
Answer:
Answer:
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Step-by-step explanation:
Nope. Perimeter = sum of all sides
P = 20 + 11 + 20 + 11 = 62 and not 64
So, it is not possible.
Join the centre O to the chord (let it be MN) & let OH be the perpendicular to the chord
OH bisects MN into 2 equal parts (each one is x/2)
OMH is a right triangle with one side =8, the second leg =x/2 & the hypotenuse = 12 (Radius)
Apply Pythagoras:
12² = 8² +(x/2)² ==>144=64 + x²/4 ==> x²=4(144-64) =320
x²=320==> x=√320 =17.88 ≈17.9
Step-by-step explanation:
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