A. n = 500 and C = 10
Substitute values into the equation and solve for k.
10 = k + 2000/500
10 = k + 4
6 = k
b. n = 250 and k = 6
Substitute values into the equation and solve for C.
C = 6 + 2000/250
C = 6 + 8
C = 14
c. C = 8.5 and k = 6
Substitute values into the equation and solve for n.
8.5 = 6 + 2000/n
2.5 = 2000/n
n = 2000/2.5
n = 800
Answer:
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Step-by-step explanation:
Answer:
450 increased by 75% = 787.5
Do you have the 4th problem typed correctly? The two given numbers have no factor (other than 1) in common (i.e., they are relatively prime) so the GCF is 1.
<span>48 = 2^4 * 3 </span>
<span>Therefore, GCF of 16a^4 b^4 + 32a^3 b^5 - 48a^2 b^6 is 16a^2 b^4, so </span>
<span>16a^4 b^4 + 32a^3 b^5 - 48a^2 b^6 = (16a^2 b^4)(a^2 + 2ab - 3b^2) = (16a</span>
Answer:
y = 2x and y = x + 3
2x = x + 3
x = 3
y = 2*3 = 6 or y = 3 + 3 = 6
yuri wrote 6 and xenia wrote 3 poems