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3 years ago

WILL GIVE BRAINLIEST sketch the graph of the following equation: y=|4-3x|

Mathematics

1 answer:

Firdavs [7]3 years ago

4 0

Answer:

attached

Step-by-step explanation:

y=|4-3x| y: positive number

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Please help I only have a few minutes left

GalinKa [24]

Answer:

4 because that's where the lines intercept

6 0

3 years ago

Please Answer!!!!

ExtremeBDS [4]

First mug holds the most

Solution:

Given that,

You are choosing between two mugs

The volume of cylinder is given as:

$V = \pi r^2h$

Where,

r is the radius and h is the height

One has a base that is 5.5 inches in diameter and a height of 3 inches

$radius = \frac{diameter}{2}$

Therefore,

$r = \frac{5.5}{2}\\\\r = 2.75$

Also, h = 3 inches

Thus volume of cylinder is given as:

$V = \pi \times 2.75^2 \times 3\\\\V = 3.14 \times 22.6875\\\\V = 71.23875 \approx 71.24$

Thus first mug holds 71.24 cubic inches

The other has a base of 4.5 inches in diameter and a height of 4 inches

$Radius = \frac{4.5}{2}\\\\r = 2.25$

h = 4 inches

Therefore,

$V = 3.14 \times 2.25^2 \times 4\\\\V = 3.14 \times 20.25\\\\V = 63.585$

Thus the second mug holds 63.585 cubic inches

On comparing, volume of both mugs,

Volume of first mug > volume of second mug

First mug holds the most

8 0

3 years ago

Reflections DO NOT preserve __________. This means the preimage (original) and the image(new) are NOT FACING the same way.

Sonbull [250]

It c okokokokokokokokokok

5 0

3 years ago

Two points in the Cartesian plane are A(2.00 m, −4.00 m) and B(−3.00 m, 3.00 m). Find the distance between them and their polar

Brrunno [24]

The distance between the two points is $d=8.6m$

The polar coordinate of A is $\left(4.47,296.57\right)$

The polar coordinate of B is $\left(4.24,135\right)$

Explanation:

The two points are $A(2,-4)$ and $B(-3,3)$

The distance between two points is given by,

$d=\sqrt{(2+3)^{2}+(-4-3)^{2}}\\d=\sqrt{(5)^{2}+(-7)^{2}}\\d=\sqrt{25+49}\\d=8.6$

Thus, the distance between the two points is $d=8.6m$

The polar coordinates of A can be written as $(Distance, tan^{-1} \frac{y}{x} )$

Distance = $\sqrt{x^{2} +y^{2} }$

Substituting $A(2,-4)$ , we get,

Distance = $\sqrt{2^{2} +(-4)^{2} }=\sqrt{4+16 }=4.47$

$tan^{-1} \frac{y}{x} =tan^{-1} \frac{-4}{2}=-63.43$

To make the angle positive, let us add 360,

$\theta=360-63.43=296.57$

The polar coordinate of A is $\left(4.47,296.57\right)$

Similarly, The polar coordinate of B can be written as $(Distance, tan^{-1} \frac{y}{x} )$

Distance = $\sqrt{x^{2} +y^{2} }$

Substituting $B(-3,3)$ , we get,

Distance = $\sqrt{(3)^{2}+(3)^{2}}=4.24$

$tan^{-1} \frac{y}{x} =tan^{-1} \frac{3}{-3}=-45$

To make the angle positive, let us add 360,

$\theta=180-45=135^{\circ}$

The polar coordinate of B is $\left(4.24,135\right)$

5 0

3 years ago

Please help me out thank you!

ANEK [815]

Answer:

Step-by-step explanation:

7 0

2 years ago