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Pavlova-9 [17]
3 years ago
13

Use distributive property to solve this problem 3(x+4)=36

Mathematics
2 answers:
adell [148]3 years ago
8 0

Distributive property example: A(B + C) = AB + AC

Simplify the equation:

3(x + 4) = 36

(3 * x) + (3 * 4) = 36

3x + 12 = 36

Now, solve for x:

3x + 12 - 12 = 36 - 12

3x = 24

3x/3 = 24/3

x = 8

Best of Luck!

olya-2409 [2.1K]3 years ago
4 0

Answer:

x=8

Step-by-step explanation:

3(x+4)=36

Divide each side by 3

3/3 (x+4)=36/3

x+4 = 12

Subtract 4 from each side

x+4-4 = 12-4

x = 8

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Expand the left side:

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Then a = 15 and b = 13, so a - b = 2.

8 0
2 years ago
Please help!!!
Alex Ar [27]

Answer:

Check bolded below

Step-by-step explanation:

1)radius = 10 in (given), diameter = 2*radius = 2(10 in) = 20 in

formula for circumference => 2πr => 2π(10)

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2)diameter = 12 ft (given), radius = 1/2*diameter = 1/2(12 ft) = 6 ft

formula for circumference => 2πr => 2π(6)

circumference = 12π ft

3)radius = 3 m (given), diameter = 2*radius = 2(3 m) = 6 m

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6 0
3 years ago
Read 2 more answers
What simple interest rate would allow $6000 to grow to an amount of $14550 in 10 years?
Harman [31]

Answer:

\boxed{ \bold{ \huge{  \boxed{ \sf{ \: 14.25 \: \% \: }}}}}

Step-by-step explanation:

Given,

Principal ( P ) = $ 6000

Amount ( A ) = $ 14550

Time ( T ) = 10 years

Rate ( R ) = ?

<u>Finding </u><u>the </u><u>Interest</u>

The sum of principal and interest is called an amount.

From the definition,

\boxed{ \sf{Amount =  \: Principal + Interest}}

plug the values

⇒\sf{14550 = 6000 + Interest}

Swap the sides of the equation

⇒\sf{6000 + Interest = 14550}

Move 6000 to right hand side and change its sign

⇒\sf{Interest = 14550 - 6000}

Subtract 6000 from 14550

⇒\sf{Interest = \: 8550 \: }

Interest = $ 8550

<u>Finding </u><u>the </u><u>rate </u>

{ \boxed{ \sf{Rate =  \frac{Interest \times 100}{Principal \times Time}}}}

plug the values

⇒\sf{ Rate = \frac{8550  \times 100}{6000 \times 10} }

Calculate

⇒\sf{Rate =  \frac{855000}{60000} }

⇒\sf{Rate = 14.25 \: \% \: }

Hope I helped!

Best regards!!

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