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Gwar [14]
3 years ago
8

Martha was recarpeting her bedroom, which was 15 feet long and 10 feet wide. How many square feet (the area) will she need to pu

rchase?
Mathematics
1 answer:
Veseljchak [2.6K]3 years ago
3 0

Answer:

150 Square feet

Step-by-step explanation:

15 feet long

10 feet wide

Area = length x width

15 x 10 = 150

150 Square feet

Hope this helped!

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You survey 200 people about the electronics they own. The results show that 33/40 people own a cell phone. Of these people, 10/1
guajiro [1.7K]
200 * 33/40 = 165 owns phones
165 * 10/11 = 150 owns phones and MP3 player

Therefore 3/4 owns both and
165 owns only phones
5 0
3 years ago
The rate of change of the function f(x) = 8 sec(x) + 8 cos(x) is given by the expression 8 sec(x) tan(x) − 8 sin(x). Show that t
liq [111]

Answer:

Shown - See explanation

Step-by-step explanation:

Solution:-

- The given form for rate of change is:

                              8 sec(x) tan(x) − 8 sin(x).

- The form we need to show:

                              8 sin(x) tan2(x)

- We will first use reciprocal identities:

                              8\frac{sin(x)}{cos^2(x)} - 8sin(x)

- Now take LCM:

                            8\frac{sin(x)- sin(x)*cos^2(x)}{cos^2(x)}

- Using pythagorean identity , sin^2(x) + cos^2(x) = 1:

                            8*sin(x)*\frac{1- cos^2(x)}{cos^2(x)} = 8*sin(x)*\frac{sin^2(x)}{cos^2(x)}

- Again use pythagorean identity tan(x) = sin(x) / cos(x):

                            8*sin(x)*tan^2(x)

8 0
3 years ago
Read 2 more answers
The biggest zucchini from Joe's farm is 2 pounds, which is 1
Vera_Pavlovna [14]

Step-by-step explanation:

It means average weight of zucchinis is 1 pound because 2 - 1 = 1

4 0
3 years ago
What are the coordinates of the orthocenter of △JKL with vertices at J(−4, −1) , K(−4, 8) , and L(2, 8) ?
Sati [7]

<u>Answer-</u>

<em>The coordinates of the orthocenter of △JKL is (-4, 8)</em>

<u>Solution-</u>

The orthocenter is the point where all three altitudes of the triangle intersect. An altitude is a line which passes through a vertex of the triangle and is perpendicular to the opposite side.

For a right angle triangle, the vertex at the right angle is the orthocentre of the triangle.

Here we are given the three vertices of the triangle are  J(-4,-1), K(-4,8) and L(2,8)

If the triangle JKL satisfies Pythagoras Theorem, then triangle JKL will be a right angle triangle.

Applying distance formula we get,

JK^2= (-4+4)^2+ (8+1)^2=0+81=81\\\\KL^2= (-4-2)^2+ (8-8)^2=36+0=36\\\\JL^2= (-4-2)^2+(8+1)^2=36+81=117

As,

\Rightarrow 117=81+36

\Rightarrow JL^2=JK^2+KL^2

\Rightarrow \text{JKL is a right angle triangle}

\Rightarrow \angle K=90^{\circ}

Therefore, the vertex at K (-4, 8) is the orthocentre.

3 0
3 years ago
Table A, B, C, Or D???<br> I’ll give brainlest
Aleks04 [339]

Answer:

i want to say C, im sorry if its wrong but im pretty sure its the right one

Step-by-step explanation:

6 0
3 years ago
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