What are the numbers x and y are sopposed to be?
It would be 6 haha I just took a test and got it right
Answer:
x ≈ ±20.086/√(t - 1)
Step-by-step explanation:
ln(t - 1) + ln(x²) = 6
Recall that lnu + lnv = ln(uv). Then
ln(t - 1) + ln(x²) = ln[(t-1)x²] = 6
Take the natural antilogarithm of each side
(t - 1)x² = e⁶
Divide each side by t - 1
x² = e⁶/(t-1)
Take the square root of each side
x = ±e³/√(t - 1)
x ≈ ±20.086/√(t - 1)
5/6 all you do is divide by 5
Answer:
Step-by-step explanation:
So first, we know (-x,-y) reflected across y axis is (x,-y). and (x,y) reflected across y axis is (-x, y). So we can apply this to get (-4,-1) to (4,-1). (2,6) to (-2,6).
