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salantis [7]
3 years ago
9

In Triangle QRS, X is the midpoint of QR, Y is the midpoint of RS, and Z is the midpoint of QS.

Mathematics
1 answer:
wlad13 [49]3 years ago
3 0

Answer:

Step-by-step explanation:

I just answered this for someone else... here is the same answer I gave them

QR + RS +SQ = perimeter

2(XR) + 2(YS) + QS = perimeter ( b/c multiplication is communicative  SQ=QS)

2*5 +  2 * 7 + 20 = perimeter

10 + 14 + 20 = p

44 = p

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9/11

Step-by-step explanation:

9/11

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3 years ago
The selling price of an item is ​$650. It is marked down by ​%10, but this sale price is still marked up from the cost of ​$450.
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nothing

Step-by-step explanation:

You get nothing because it would make -43256742984

7 0
3 years ago
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Elina [12.6K]
Answer: 880

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6 0
3 years ago
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If the endpoints of the diameter of a circle are (−8, −6) and (−4, −14), what is the standard form equation of the circle?
kondaur [170]

Equation of the circle is (x+6)^{2}+(y+10)^{2}=20.

Solution:

The endpoints of the diameter of a circle are (–8, –6) and (–4, –14).

Center of the circle = Mid point of the diameter

Mid point formula:

$P(x, y)=\left(\frac{x_{1}+x_{2}}{2}, \frac{y_{1}+y_{2}}{2}\right)

Here, x_1=-8, y_1=-6, x_2=-4, y_2=-14

$P(x, y) =\left(\frac{-8-4}{2}, \frac{-6-14}{2}\right)

$P(x, y) =\left(\frac{-12}{2}, \frac{-20}{2}\right)

$P(x, y) =(-6, -10)

Center of the circle = (–6, –10)

Radius is the distance between center and any endpoint of the diameter.

To calculate the radius using distance formula.

r=\sqrt{\left(x_{2}-x_{1}\right)^{2}+\left(y_{2}-y_{1}\right)^{2}}

Here, x_1=-6, y_1=-10, x_2=-8, y_2=-6

r=\sqrt{\left(-8-(-6)\right)^{2}+\left(-6-(-10)}\right)^{2}}

r=\sqrt{(-8+6)^{2}+(-6+10)^{2}}

r=\sqrt{(-2)^{2}+(4)^{2}}

r=\sqrt{20} units

The standard form of the equation of a circle is

(x-a)^{2}+(y-b)^{2}=r^{2}, where (a, b) are center and r is the radius.

Here, center = (–6, –10) and r=\sqrt{20}

(x-(-6))^{2}+(y-(-10))^{2}={(\sqrt{20})} ^{2}

(x+6)^{2}+(y+10)^{2}=20

Equation of the circle is (x+6)^{2}+(y+10)^{2}=20.

4 0
3 years ago
Will a frying pan with a circumference of 25.12 inches fit on an electric burner with a 4-inch radius?
Leokris [45]

Answer:

Yes

Step-by-step explanation:

25.12 inches of circumference is equal to the radius of 3.998 inches

4 inches > 3.998 inches

Therefore it fits


8 0
3 years ago
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