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kirill115 [55]
3 years ago
15

If tommy rode his bike 4.3 miles a day, 3 days a week for 5 years delivering news papers and he dropped 22.7 newspapers every 1/

4 mile. How many newspapers did tommy drop?
Mathematics
1 answer:
geniusboy [140]3 years ago
6 0

Answer:

277 848 newspapers.

Step-by-step explanation:

Find out how much newspaper he drops for 4.3 miles.

1/4 = 0.25

4.3 miles ÷ 0.25 = 17.2

= 17

17 x 22.7 = 385.9

(Newspapers be dropped a day)

1 week of dropping newspapers = 385.9 x 3 = 1157.7

1 month of dropping newspapers = 1157.7 x 4 =

4630.8

1 year = 12 months

5 years = 12 x 5 = 60 months.

5 years/60 months of dropping newspapers = 4630.8 x 60 = 277 848

Tommy dropped 277 848 newspapers.

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Answer:

V = 1385.44

Step-by-step explanation:

The equation for volume is V = π r 2 h! Where V = volume, r = radius <em>(half the diameter)</em>, and h = height. Now lets substitute what we know into this equation!

<em>Since we are giving the diameter (14) we must divide by 2 to find the radius.</em>

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7 0
3 years ago
According to the U.S. Census Bureau, 42% of men who worked at home were college graduates. In a sample of 480 women who worked a
Likurg_2 [28]

Answer:

1) 0.327 - 0.539 \sqrt{\frac{0.327(1-0.327)}{480}}=0.315

The point estimate for the proportion of college graduates among women who work at home is 0.327

2) 0.327 - 0.539 \sqrt{\frac{0.327(1-0.327)}{480}}=0.315

0.327 + 0.539 \sqrt{\frac{0.327(1-0.327)}{480}}=0.339

The 80% confidence interval is given by (0.315; 0.339)

Step-by-step explanation:

For this case we have the following info given:

X = 157 represent the women who worked at home who were college graduates

n = 480 the sample size selected

Part 1

In order to find the proportion of college graduates among women who work at home and we can use the following formula:

\hat p=\frac{X}{n} = \frac{157}{480}= 0.327

The point estimate for the proportion of college graduates among women who work at home is 0.327

Part 2

Construct an 80% confidence interval for the proportion of women who work at home who are college graduates. Round the answer to three decimal places. An 80% confidence interval for the proportion of women who work at home Is < p <

The confidence interval for the true proportion would be given by this formula

\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}

For the 80% confidence interval the value for the significance is\alpha=1-0.8=0.2 and \alpha/2=0.1, the critical value would be given by:

z_{\alpha/2}=0.539

And replacing we goot:

0.327 - 0.539 \sqrt{\frac{0.327(1-0.327)}{480}}=0.315

0.327 + 0.539 \sqrt{\frac{0.327(1-0.327)}{480}}=0.339

The 80% confidence interval is given by (0.315; 0.339)

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