Answer:
69.15% probability that a randomly selected customer spends less than $105 at this store
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

What is the probability that a randomly selected customer spends less than $105 at this store?
This is the pvalue of Z when X = 105. So



has a pvalue of 0.6915
69.15% probability that a randomly selected customer spends less than $105 at this store
5/8 is 0.625 add 11 it becomes 11.625 multiply it by 0.5 it becomes 5.8125
in fraction form 11 65/72
9000 is a 4 digit number that is divisible by 9 and 8. ( 9000/9 = 1000) and ( 9000/8 = 1125 )