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zhannawk [14.2K]
3 years ago
12

Mr. Watkins earns $35 an hour at his new job. During a typical month, he works a total of 160 hours. Mrs. Watkins is a homemaker

. After meeting the estimated monthly expenses, how much money will the family have left to spend on other items?
A) $1150
B) $1322
C) $1445
D) $1500
Mathematics
1 answer:
aleksley [76]3 years ago
8 0
What are the monthly expenses? Here is the total money Mr.Watkins makes, $5600
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A gambler has a coin which is either fair (equal probability heads or tails) or is biased with a probability of heads equal to 0
yawa3891 [41]

Answer:

(a) 0.1719

(b) 0.3504

Step-by-step explanation:

For every coin the number of heads follows a Binomial distribution and the probability that x of the 10 times are heads is equal to:

P(x)=\frac{n!}{x!(n-x)!}*p^x*(1-p)^{10-x}

Where n is 10 and p is the probability to get head. it means that p is equal to 0.5 for the fair coin and 0.3 for the biased coin

So, for the fair coin, the probability that the number of heads is less than 4 is:

P(x

Where, for example, P(0) and P(1) are calculated as:

P(0)=\frac{10!}{0!(10-0)!}*0.5^0*(1-0.5)^{10-0}=0.0009\\P(1)=\frac{10!}{1!(10-1)!}*0.5^1*(1-0.5)^{10-1}=0.0098

Then, P(x, so there is a probability of 0.1719 that you conclude that the coin is biased given that the coin is fair.

At the same way, for the biased coin, the probability that the number of heads is at least 4 is:

P(x\geq4 )=P(4)+P(5)+P(6)+...+P(10)

Where, for example, P(4) is calculated as:

P(4)=\frac{10!}{4!(10-4)!}*0.3^4*(1-0.3)^{10-4}=0.2001

Then, P(x\geq4 )=0.3504, so there is a probability of 0.3504 that you conclude that the coin is fair given that the coin is biased.

7 0
3 years ago
Sonja uses 8 of the 12 eggs in her dozen eggs to make a breakfast casserole. Olga uses 5/6 of a dozen eggs to make scrambled egg
GREYUIT [131]

Answer:

Olga will use 10 eggs, while Sonja will use 8, thus Olga will use more eggs.

Step-by-step explanation:

Given that Sonja uses 8 of the 12 eggs in her dozen eggs to make a breakfast casserole, while Olga uses 5/6 of a dozen eggs to make scrambled eggs, the following calculations must be performed to determine who uses more eggs:

Sonja = 8/12 = 0.666 x 12 = 8

Olga = 5/6 = 0.83333 x 12 = 10

Therefore, Olga will use 10 eggs, while Sonja will use 8, thus Olga will use more eggs.

4 0
3 years ago
How many solutions does the system have? <br> {2x+2y=8 <br> {3x+y=8 2x+2y=8 ​
umka2103 [35]

Answer:

Step-by-step explanation:

first we put them in y = mx + b form...then we compare the slopes and the y int's. In y = mx + b form, the slope is in the m position and the y int is in the b position.

2x + 2y = 8

2y = -2x + 8

y = -x + 4......slope here is -1 and y int is 4

3x + y = 8

y = -3x + 8.....slope here is -3 and y int is 8

This system has 1 solution <===

================================

learn this...it helps

* if there are different slopes and different y int, then there is 1 solution

* if there are the same slopes and different y int, then there is no solutions because u have parallel lines

* if there are same slopes and same y int, there is infinite solutions because u have the same line

4 0
3 years ago
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Help me pls i keep getting 3/2 but thats not the answer
Gemiola [76]

\huge\text{Hey there!}

\large\boxed{\mathsf{\dfrac{6x^2}{y^3}}}\\\\\large\boxed{= \mathsf{\dfrac{6(4^2)}{4^3}}}\\\\\large\boxed{= \mathsf{\dfrac{6(4\times4)}{4\times4\times4}}}\\\\\large\boxed{= \mathsf{\dfrac{96}{16\times4}}}}\\\\\large\boxed{= \mathsf{\dfrac{96}{64}}}\\\large\boxed{\approx \mathsf{\dfrac{96\div32}{64\div32}}}\\\large\boxed{\approx \mathsf{\dfrac{3}{2} \rightarrow \bf \dfrac{96}{64}}}

\huge\text{Thus, your answer is: \boxed{\mathsf{Option\ A. } \  \mathsf{\dfrac{96}{64}}}}\huge\checkmark

\huge\text{Good luck on your assignment \& enjoy}\\\huge\text{your day!}

~\frak{Amphitrite1040:)}

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3 years ago
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kykrilka [37]

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