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3 years ago

1. Find the circumference of a circle with a radius of 12 cm. Round decimal answer to the

Mathematics

2 answers:

Nana76 [90]3 years ago

5 0

Answer:

b. 75.40

Step-by-step explanation:

The circumference of a circle is the perimeter of the circle. To find the perimeter we would use the formula ⇒ 2 × π × r ⇔ or π × d ← where r is the radius and d is the diameter .

So lets substitute in the values

2 × π × r

Radius = 12

2 × π × 12 = 24 π = 75.3982236862

So the answer is b. 75.40

Wewaii [24]3 years ago

5 0

Answer:

b. 75.40

Step-by-step explanation:

Circumference = 2pi × r

= 2pi × 12

= 24pi

= 75.39822369

Nearest hundredth: 75.40 cm

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Dr. W Sweet Rides Car Rental charges a flat fee of $24 and an additional $0.35 for every mile the car is driven. Which function

kompoz [17]

Step-by-step explanation:

this is a strange rental company charging no daily fees.

but ok.

so, we have a fixed part of the cost : $24

we have to pay that no matter how many miles we drive. even for 0 miles, just to get the keys to the car.

and then we pay $0.35 for every mile driven.

that makes our function

C(x) = 0.35x + 24

and if we drive 40 miles, that makes x = 40.

C(24) = 0.35×40 + 24 = 14 + 24 = $38

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3 0

3 years ago

Health insurance benefits vary by the size of the company (the Henry J. Kaiser Family Foundation website, June 23, 2016). The sa

xxMikexx [17]

Answer:

$\chi^2 = \frac{(32-42)^2}{42}+\frac{(18-8)^2}{8}+\frac{(68-63)^2}{63}+\frac{(7-12)^2}{12}+\frac{(89-84)^2}{84}+\frac{(11-16)^2}{16}=19.221$

Now we can calculate the degrees of freedom for the statistic given by:

$df=(rows-1)(cols-1)=(3-1)(2-1)=2$

And we can calculate the p value given by:

$p_v = P(\chi^2_{2} >19.221)=0.000067$

And we can find the p value using the following excel code:

"=1-CHISQ.DIST(19.221,2,TRUE)"

Since the p values is higher than a significance level for example $\alpha=0.05$ , we can reject the null hypothesis at 5% of significance, and we can conclude that the two variables are dependent at 5% of significance.

Step-by-step explanation:

Previous concepts

A chi-square goodness of fit test "determines if a sample data matches a population".

A chi-square test for independence "compares two variables in a contingency table to see if they are related. In a more general sense, it tests to see whether distributions of categorical variables differ from each another".

Solution to the problem

Assume the following dataset:

Size Company/ Heal. Ins. Yes No Total

Small 32 18 50

Medium 68 7 75

Large 89 11 100

_____________________________________

Total 189 36 225

We need to conduct a chi square test in order to check the following hypothesis:

H0: independence between heath insurance coverage and size of the company

H1: NO independence between heath insurance coverage and size of the company

The statistic to check the hypothesis is given by:

$\sum_{i=1}^n \frac{(O_i -E_i)^2}{E_i}$

The table given represent the observed values, we just need to calculate the expected values with the following formula $E_i = \frac{total col * total row}{grand total}$