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3 years ago

“x is at most –5 or at least 7.”

Mathematics

1 answer:

uysha [10]3 years ago

7 0

<span>x is at most –5 or at least 7 is written as $x \leq -5 \ or \ x \geq 7$ </span>

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Determine the quotient:2 4/7 ÷1 3/6

Lisa [10]

12/7. You put the numbers into mixed numbers giving you 18/7 and 9/6. For division you flip the second fraction and multiply them together. So you do 18/7 x 6/9. You're also able to cross cancel 18 and 9 giving you 2/7 x 6/1. 6 x 2 is 12 and 7 x 1 is 7. Your answer is 12/7.

3 0

4 years ago

Please help, it's on Pythagoras theorem!

kondor19780726 [428]

C squared = a squared+ b squared (formula)

so therefore
(c longest side) (this is your x)
(a and b shorter sides).

C squared = 5 squared + 3 squared
C squared = 25 + 9
C squared = 31

Then you find the square root of c (which is just getting rid of the squared sign) and the square root of 31 And that is your answer

Hope this helps!!

3 0

3 years ago

Identify the property being demonstrated

My name is Ann [436]

Answer:

$\: \: \: \: \: \: \: \: \: \: \dfrac{x}{5} = 7 \\ \implies \: x = 7 \times 5 \\ \implies \: x = 35$

So,b. multiplication

3 0

3 years ago

Read 2 more answers

Graph the line with a slope of <img src="https://tex.z-dn.net/?f=%5Cfrac%7B5%7D%7B3%7D" id="TexFormula1" title="\frac{5}{3}" alt

balu736 [363]

I don’t know sorry please somebody else can help you

8 0

3 years ago

Sal's Sandwich Shop sells wraps and sandwiches as part of its lunch specials. The profit on every sandwich is $2 and the profit

coldgirl [10]

Changing the equation into slope form: $y = mx + c$ , where $m$ is the slope [gradient] and $c$ is the y-intercept.

$2x+3y=1470$
$3y = -2x+1470$
$y= - \frac{2}{3}x+ \frac{1470}{3}$
$y=- \frac{2}{3}x+490$

The gradient is $- \frac{2}{3}$ and y-intercept is at $y=490$

Graphing $y=- \frac{2}{3}x+490$ using slope-intercept method:
a) The slope is a negative slope. The line will go 'down hill'
b) The line must pass the point (0, 490)
c) The line will intercept the x-axis at y = 0
   $0 = - \frac{2}{3}x+490$
   $\frac{2}{3}x = 490$
   $2x = 1470$
   $x = \frac{1470}{2}$
   $x = 735$
So, x-intercept is at (735, 0)

The graph of this function is shown below. The intercepts are labelled at:
y = 490
x = 735

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Next month's profit equation

$2x+3y=1593$

Rewriting this into slope-equation form

$3y = -2x+1593$
$y=- \frac{2}{3}+ \frac{1593}{3}$
$y= - \frac{2}{3}+531$

The gradient, $m$ , equals to $- \frac{2}{3}$
The y-intercept, $c$ , equals to 531

The equation still has the same gradient with last month's profit equation but different y-intercept.

-------------------------------------------------------------------------------------------------------------

A linear graph show points of (0, 300) and (450, 0)

We work out the slope:
$\frac{300-0}{0-450} = \frac{300}{-450}=- \frac{20}{30} =- \frac{2}{3}$

Y-intercept at x = 0, so it's at y = 300

Equation $y = - \frac{2}{3}+300$

6 0

3 years ago