3 years ago

The average of three different positive integers is 8. What is the largest integer that could be one of them?

1 answer:

galina1969 [7]3 years ago

4 0

Answer:22

Step-by-step explanation: the smallest the other two can be is 1 so you have to multiply 8 with 3, that equals 24, then you have to subtract 2 (1+1) and that gives you 22.

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ryzh [129]

Answer:

TanФ=-1.793

Step-by-step explanation:

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$Sin(A)=\sqrt{1-Cos^{2} (A)}$

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$Tan(A) =\frac{\sqrt{1-Cos^{2}(A) } }{Cos(A)} \\Tan(A) =\frac{\sqrt{1-(-.487)^{2} } }{-.487}=-1.793433202$

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Harlamova29_29 [7]

Answer:

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Step-by-step explanation:

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Arturiano [62]

Answer:

The correct answer would 3/4 cups of sugar

Step-by-step explanation:

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2 years ago

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kumpel [21]

Answer:

all in all it's y=x

Step-by-step explanation:

A (4,1); B (0,-2)

G=delta y

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delta x

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4-0

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jeyben [28]

I posted what I have in the other post it's same question

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