20 subtracted from the product of 2 and a number is 14.
2 answers:
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Answer:
The largest even integer is 0
Step-by-step explanation:
Given as :
The sum of four consecutive even number = - 12
Let The first even number = 2 x
The second even number = (2 x + 2)
The third even number = (2 x + 4)
The fourth even number = (2 x + 6)
<u>According to question</u>
sum of four consecutive even number = - 12
Or, 2 x + (2 x + 2) + (2 x + 4) + (2 x + 6) = - 12
Or, (2 x + 2 x + 2 x + 2 x) + (2 + 4 + 6) = - 12
Or, 8 x + 12 = - 12
Or, 8 x = - 12 - 12
Or, 8 x = - 24
∴ x =
i.e x = - 3
now, putting the value of x
The first even number = 2 × - 3 = - 6
The second even number = (2 × - 3 + 2) = - 6 + 2 = - 4
The third even number = (2 × - 3 + 4) = - 6 + 4 = - 2
The fourth even number = (2 × - 3 + 6) = - 6 + 6 = 0
So, The largest even integer = 0
Hence, The largest even integer is 0 Answer