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Vaselesa [24]
3 years ago
12

The area of a rectangle was 15 cm. Every dimension was multiplied by a scale factor and the new area was 3.75 cm. What was the s

cale factor?
Mathematics
1 answer:
Pavlova-9 [17]3 years ago
4 0
The scale factor was .25
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Romeo had pound of fudge left. He divided the remaining fudge into -pound 5 16 bags. Write and solve an equation that models the
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Answer:

The solution of the given trigonometric equation

                   x = \frac{\pi }{6}

Step-by-step explanation:

<u><em>Step(i):</em></u>-

Given  

                cos( 3x - \frac{\pi }{3} )  = \frac{\sqrt{3} }{2}

                  cos( 3x - \frac{\pi }{3} )  = cos (\frac{\pi }{6} )

                      3x - \frac{\pi }{3}  =  \frac{\pi }{6}

                      3x - \frac{\pi }{3  } + \frac{\pi }{3}   =  \frac{\pi }{6} + \frac{\pi }{3}

                      3x = \frac{2\pi +\pi }{6} = \frac{3\pi }{6} = \frac{\pi }{2}

                     x = \frac{\pi }{6}

<u><em>Step(ii)</em></u>:-

The solution of the given trigonometric equation

                   x = \frac{\pi }{6}

<u><em>verification </em></u>:-

      cos( 3x - \frac{\pi }{3} )  = \frac{\sqrt{3} }{2}

put  x = \frac{\pi }{6}

    cos( 3(\frac{\pi }{6})  - \frac{\pi }{3} )  = \frac{\sqrt{3} }{2}

    cos (\frac{\pi }{6} ) = \frac{\sqrt{3} }{2} \\\\\frac{\sqrt{3} }{2} =  \frac{\sqrt{3} }{2}

Both are equal

∴The solution of the given trigonometric equation

                   x = \frac{\pi }{6}

                     

4 0
2 years ago
If p and q vary inversely and p is 10 when q is 19 , determine q when p is equal to 2
GenaCL600 [577]
You divide 10 by 5 is two so 19 decided by five is 3.8
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3 years ago
Read 2 more answers
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