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3 years ago

7

50 POINTS FOR WHOEVER ANSWERS CORRECTLY!!!!! Rotate these coordinates 270 degrees counterclockwise around the origin and then tr

anslate 5 units up.

1 answer:

Colt1911 [192]3 years ago

7 0

(-6,4) (-4,-2) (1,-4) (0,-8)

You might be interested in

Triangle ABC is transformed to obtain triangle A′B′C′:

aleksley [76]

Exactly what the other guy said

7 0

3 years ago

Read 2 more answers

1. Find measure of angle GBC<br> A. 55°<br> B. 125°<br> C. 45°<br> D. 60°<br> (Show work)

mihalych1998 [28]

Answer:

A. 55°

Step-by-step explanation:

So the line goes through two angles, 125° and 55°

Lets check, does the angle look larger than 90°

Remember, 90° mean the line is perpendicular, or goes straight up.

I see that it is not. The angle that is less than 90° (55°) is correct.

If my answer is incorrect, pls correct me!

If you like my answer and explanation, mark me as brainliest!

-Chetan K

3 0

3 years ago

Can someone please help me, I need to know the missing side length (x) using trigonometric ratios.

KatRina [158]

Answer:

x = 5.34

Step-by-step explanation:

The reference angle is 24 degrees. I'm sure you are aware from the square at the other base angle that is a right triangle. Right triangles have ratios by which we can determine missing side and angle measures. The sin of a reference angle has a ratio that is side opposite/hypotenuse. The cos of a reference angle has a ratio that is side adjacent/hypotenyse. The tan of a reference angle has a ratio that is side opposite/side adjacent.

We need to decide which of these fits our needs according to the angle and sides we are given and need to find. We have the reference angle as 24 degrees, we have the side adjacent to this angle as 12. We are looking for x, which is the side opposite the reference angle. Looking to what our definitions are for each ratio, the sides opposite and adjacent are defining the tan of the reference angle. Setting up the ratio then looks like this:

$tan(24)=\frac{x}{12}$

Multiply both sides by 12 to get

12 tan(24) = x

Do this on your calculator in DEGREE mode to get that

x = 5.342744224

Not sure what your teacher has you round to, but I usually have my students give me 2 decimal places

6 0

4 years ago

Solve the initial value problem where y′′+4y′−21 y=0, y(1)=1, y′(1)=0 . Use t as the independent variable.

igor_vitrenko [27]

Answer:

$y = \frac{7}{10} e^{3(t - 1)} + \frac{3}{10}e^{-7(t - 1)}$

Step-by-step explanation:

y′′ + 4y′ − 21y = 0

The auxiliary equation is given by

m² + 4m - 21 = 0

We solve this using the quadratic formula. So

$m = \frac{-4 +/- \sqrt{4^{2} - 4 X 1 X (-21))} }{2 X 1}\\ = \frac{-4 +/- \sqrt{16 + 84} }{2}\\= \frac{-4 +/- \sqrt{100} }{2}\\= \frac{-4 +/- 10 }{2}\\= -2 +/- 5\\= -2 + 5 or -2 -5\\= 3 or -7$

So, the solution of the equation is

$y = Ae^{m_{1} t} + Be^{m_{2} t}$

where m₁ = 3 and m₂ = -7.

So,

$y = Ae^{3t} + Be^{-7t}$

Also,

$y' = 3Ae^{3t} - 7e^{-7t}$

Since y(1) = 1 and y'(1) = 0, we substitute them into the equations above. So,

$y(1) = Ae^{3X1} + Be^{-7X1}\\1 = Ae^{3} + Be^{-7}\\Ae^{3} + Be^{-7} = 1 (1)$

$y'(1) = 3Ae^{3X1} - 7Be^{-7X1}\\0 = 3Ae^{3} - 7Be^{-7}\\3Ae^{3} - 7Be^{-7} = 0 \\3Ae^{3} = 7Be^{-7}\\A = \frac{7}{3} Be^{-10}$

Substituting A into (1) above, we have

$\frac{7}{3}B e^{-10}e^{3} + Be^{-7} = 1 \\\frac{7}{3}B e^{-7} + Be^{-7} = 1\\\frac{10}{3}B e^{-7} = 1\\B = \frac{3}{10} e^{7}$

Substituting B into A, we have

$A = \frac{7}{3} \frac{3}{10} e^{7}e^{-10}\\A = \frac{7}{10} e^{-3}$

Substituting A and B into y, we have

$y = Ae^{3t} + Be^{-7t}\\y = \frac{7}{10} e^{-3}e^{3t} + \frac{3}{10} e^{7}e^{-7t}\\y = \frac{7}{10} e^{3(t - 1)} + \frac{3}{10}e^{-7(t - 1)}$

So the solution to the differential equation is

$y = \frac{7}{10} e^{3(t - 1)} + \frac{3}{10}e^{-7(t - 1)}$

6 0

4 years ago

Find the area of the shade regions. Give your answer as a completely simplify exact value in terms of pie(no approximation). a=

mr Goodwill [35]

Answer:

<u>125.6 in²</u>

Step-by-step explanation:

Area shaded :

2 × Sector (72°)
2 x πr² x θ/360
2 x 3.14 x 100 x 72/360
6.28 x 100 x 1/5
20 x 6.28
<u>125.6 in²</u>

4 0

2 years ago