Question

Help please will mark best answer

Answer 1

I figured out the first question, the second one in lost on.

$\frac{(6-x)}{x^2+3x-28} / \frac{x^2-36}{x^2+5x-36}$

Factor both of the equations, numerator and denominator

$\frac{(6-x)}{(x+7)(x-4)}* \frac{(x+6)(x-6)}{(x+9)(x-4)}$

Cancel the like factors *excuse the zero im just showing you*

$\frac{(0)}{(x+7)} *\frac{(x+6)}{(x-9)}$

Combine frunctions

$\frac{(6+x)}{(x-9)(x+7)}$

x-9=0
x+7=0

Restrictions are 9 and -7