Answer:
standard deviation = 3.0331
Step-by-step explanation:
You can solve for this two different ways.
If you have a TI-84 calculator or something similar, type all the data into list 1. Then click the stat button, then the calc button, then 1-vars stats. This will give you mean, standard deviation, median, mode, etc.
If you are solving by hand, find the different between each data point and the mean. Square these numbers and find the average. Then take the square root of that.
3^2 + 4^2 + 1^2 + 2^2 + 4^2 = 46
46/5 = 9.2
square root of 9.2 = 3.0331
Hope this is helpful!!!!!!!!!!! :)
Answer:
-x^2 - 20x -4 = 0
Step-by-step explanation:
I assume you meant (x-8)(2x+3) = (3x-5)(x+4).
Perform the two indicated multiplications and then combine like terms:
2x^2 + 3x - 16x - 24 = 3x^2 + 12x - 5x - 20
Combine the x terms on each side:
2x^2 - 13x - 24 = 3x^2 + 7x - 20
Subtract 3x^2 from both sides:
-x^2 - 13x - 24 = 7x - 20
Subtract 7x from both sides:
-x^2 - 20x - 24 = -20
Add 20 to both sides:
-x^2 - 20x -4 = 0 This is the desired quadratic equation.
Answer:
c because
Step-by-step explanation:
in math, we are learning this. 3/5 is equal o 3 divided to 5 because "/"is a division sign
Answer:
The answer to your question is there were 88 children
Step-by-step explanation:
Data
Total number of people = 188
total cost = $5040
12 more adults than seniors
number of children = ?
adults = a
children = c
Process
1.- Write equations that help to solve this problem
a + c = 188 Equation l
a = c + 12 Equation ll
2.- Solve by substitution. Substitute equation equation ll in equation l
(c + 12) + c = 188
-Solve for c
c + 12 + c = 188
2c + 12 = 188
2c = 188 - 12
2c = 176
c = 176 / 2
c = 88
3.- Conclusion
There were 88 children
The situation can be modeled by a geometric sequence with an initial term of 284. The student population will be 104% of the prior year, so the common ratio is 1.04.
Let \displaystyle PP be the student population and \displaystyle nn be the number of years after 2013. Using the explicit formula for a geometric sequence we get
{P}_{n} =284\cdot {1.04}^{n}P
n
=284⋅1.04
n
We can find the number of years since 2013 by subtracting.
\displaystyle 2020 - 2013=72020−2013=7
We are looking for the population after 7 years. We can substitute 7 for \displaystyle nn to estimate the population in 2020.
\displaystyle {P}_{7}=284\cdot {1.04}^{7}\approx 374P
7
=284⋅1.04
7
≈374
The student population will be about 374 in 2020.
