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DIA [1.3K]
3 years ago
5

The width of a rectangle is 4 less than half the length. If I represents the

Mathematics
2 answers:
anastassius [24]3 years ago
8 0

Answer: w=L - 4

Step-by-step explanation:

w= width

L= length

w= L - 4

LiRa [457]3 years ago
6 0

Answer:

w=l-4

Step-by-step explanation:

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What’s the slope of the line that passes through 5,10 and 7,12
Marrrta [24]

Slope of the line passes through (5,10) and (7,12) is 1.

Step-by-step explanation:

Given,

The two points are (5,10) and (7,12).

To find the slope passing through the given points.

Formula

The slope of the line passing through (x_{1} ,y_{1}) and (x_{2} ,y_{2}) is \frac{y_{2} -y_{1} }{x_{2} -x_{1} }

Now, putting x_{1} =5,y_{1}=10, x_{2}=7, y_{2} =12 we get,

Slope = \frac{12-10}{7-5} = \frac{2}{2} = 1

Hence,

Slope of the line passes through (5,10) and (7,12) is 1.

7 0
3 years ago
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Calculate the sum. 1.075 + 27.105 *
Molodets [167]
I believe the answer is 28.18
5 0
2 years ago
The deer population in a national wildlife refuge has been decreasing by 5% each year.
mestny [16]

Answer:

750(1-\frac{5}{100})^{n}

Step-by-step explanation:

3 0
3 years ago
A bag contains two six-sided dice: one red, one green. The red die has faces numbered 1, 2, 3, 4, 5, and 6. The green die has fa
gayaneshka [121]

Answer:

the probability the die chosen was green is 0.9

Step-by-step explanation:

Given that:

A bag contains two six-sided dice: one red, one green.

The red die has faces numbered 1, 2, 3, 4, 5, and 6.

The green die has faces numbered 1, 2, 3, 4, 4, and 4.

From above, the probability of obtaining 4 in a single throw of a fair die is:

P (4  | red dice) = \dfrac{1}{6}

P (4 | green dice) = \dfrac{3}{6} =\dfrac{1}{2}

A die is selected at random and rolled four times.

As the die is selected randomly; the probability of the first die must be equal to the probability of the second die = \dfrac{1}{2}

The probability of two 1's and two 4's in the first dice can be calculated as:

= \begin {pmatrix}  \left \begin{array}{c}4\\2\\ \end{array} \right  \end {pmatrix} \times  \begin {pmatrix} \dfrac{1}{6}  \end {pmatrix}  ^4

= \dfrac{4!}{2!(4-2)!} ( \dfrac{1}{6})^4

= \dfrac{4!}{2!(2)!} \times ( \dfrac{1}{6})^4

= 6 \times ( \dfrac{1}{6})^4

= (\dfrac{1}{6})^3

= \dfrac{1}{216}

The probability of two 1's and two 4's in the second  dice can be calculated as:

= \begin {pmatrix}  \left \begin{array}{c}4\\2\\ \end{array} \right  \end {pmatrix} \times  \begin {pmatrix} \dfrac{1}{6}  \end {pmatrix}  ^2  \times  \begin {pmatrix} \dfrac{3}{6}  \end {pmatrix}  ^2

= \dfrac{4!}{2!(2)!} \times ( \dfrac{1}{6})^2 \times  ( \dfrac{3}{6})^2

= 6 \times ( \dfrac{1}{6})^2 \times  ( \dfrac{3}{6})^2

= ( \dfrac{1}{6}) \times  ( \dfrac{3}{6})^2

= \dfrac{9}{216}

∴

The probability of two 1's and two 4's in both dies = P( two 1s and two 4s | first dice ) P( first dice ) + P( two 1s and two 4s | second dice ) P( second dice )

The probability of two 1's and two 4's in both die = \dfrac{1}{216} \times \dfrac{1}{2} + \dfrac{9}{216} \times \dfrac{1}{2}

The probability of two 1's and two 4's in both die = \dfrac{1}{432}  + \dfrac{1}{48}

The probability of two 1's and two 4's in both die = \dfrac{5}{216}

By applying  Bayes Theorem; the probability that the die was green can be calculated as:

P(second die (green) | two 1's and two 4's )  = The probability of two 1's and two 4's | second dice)P (second die) ÷ P(two 1's and two 4's in both die)

P(second die (green) | two 1's and two 4's )  = \dfrac{\dfrac{1}{2} \times \dfrac{9}{216}}{\dfrac{5}{216}}

P(second die (green) | two 1's and two 4's )  = \dfrac{0.5 \times 0.04166666667}{0.02314814815}

P(second die (green) | two 1's and two 4's )  = 0.9

Thus; the probability the die chosen was green is 0.9

8 0
3 years ago
IMAGE ATTACHED please help giving 50 points
alexdok [17]

Answer:

(4,1)

Step-by-step explanation:

when points are reflected on the y-axis you switch your x coordinate from positive to negative or the other way around the y coordinate stays the same.

(2,1) reflected is (-2,1)

(7,4) reflected is (-7,4)

(-8,-4) reflected is (8,-4)

so (-4,1) reflected is (4,1)

5 0
2 years ago
Read 2 more answers
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