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ddd [48]
2 years ago
13

Help please . Thank you !!

Mathematics
1 answer:
dmitriy555 [2]2 years ago
4 0

Answer:

A=25m

Step-by-step explanation:

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Suppose the sediment density (g/cm3 ) of a randomly selected specimen from a certain region is known to have a mean of 2.80 and
Irina18 [472]

Answer:

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Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 2.80

Standard Deviation, σ = 0.85

Sample size,n = 35

We are given that the distribution of sediment density is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

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=\dfrac{\sigma}{\sqrt{n}} = \dfrac{0.85}{\sqrt{35}} = 0.1437

P(sample average sediment density is at most 3.00)

P( x \leq 3.00) = P( z \leq \displaystyle\frac{3.00 - 2.80}{0.1437}) = P(z \leq 1.3917)

Calculation the value from standard normal z table, we have,  

P(x \leq 3.00) = 0.918

0.918 is the probability that the sample average sediment density is at most 3.00

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3 years ago
Oscar has $1.00 in quarters and dimes. He has 7 coins altogether. How many coins of each kind does he have?
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Answer:

2 quarters and 5 dimes

Step-by-step explanation:

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