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agasfer [191]
3 years ago
6

How many cubic centimeters is 5 cubic meters.

Mathematics
2 answers:
tresset_1 [31]3 years ago
4 0
The key to solving this question is first knowing how many cubic cm are in one cubic m:

The ratio is always 1000000 cubic cm in 1 cubic meter.

Knowing this, we calculate how many cubic cm are in 5 cubic meters!

<u>1000000 cubic cm </u>= <u>1 </u><span><u>cubic m</u>
      x </span>cubic cm           5 cubic m

x = 1000000 cubic cm x 5 cubic m ÷ 1 cubic m
x = 5<span>000000 cubic cm

Hope this helps!
Feel free to message me if you have any questions :)</span>
shepuryov [24]3 years ago
4 0

Answer:

5000000 cubic centimeters

Step-by-step explanation:

5 cubic meters

Changing cubic meters into cubic centimeters, we multiply by 1,000,000

So

5*1000000 cubic centimeters

So we get

5000000 cubic centimeters

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A tank is filled at a constant rate. 10 minutes after filling is started, the tank contains 4.8L of water. After 35 minutes the
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Answer:

Part A)

0.1 liters per minute.

Part B)

There was initially 3.8 liters of water.

\displaystyle V(t) = 0.1(t - 10) + 4.8

Part C)

562 minutes.

Step-by-step explanation:

A tank is filled at a constant rate. After 10 minutes, the tank contains 4.8 L of water and after 35 minutes, the tank contains 7.3 L of water.

Part A)

We can represent the current data with two points: (10, 4.8) and (35, 7.3). The <em>x-</em>coordinate is measured in minutes since the tank began to be filled and the <em>y-</em>coordinate is measured in how full the tank is in liters.

To find the rate at which the tank is being filled, find the slope between the two points:

\displaystyle m = \frac{\Delta y}{\Delta x} = \frac{(7.3)-(4.8)}{(35)-(10)} = \frac{2.5}{25} = 0.1

In other words, the rate at which the tank is being filled is 0.1 liters per minute.

Part B)

To find the function of the volume of the tank, we can use the point-slope form to first find its equation:

\displaystyle y - y_1 = m( x - x_1)

Where <em>m</em> is the slope/rate of change and (<em>x</em>₁, <em>y</em>₁) is a point.

We will substitute 0.1 for <em>m</em> and let (10, 4.8) be the point. Hence:

\displaystyle y - (4.8) = 0.1(x - 10)

Simplify:

\displaystyle y = 0.1(x-10) + 4.8

Since <em>y</em> represent how full the tank is and <em>x</em> represent the time in minutes since the tank began to be filled, we can substitute <em>y</em> for V(t) and <em>x</em> for <em>t</em>. Thus, our function is:

<em />\displaystyle V(t) = 0.1(t - 10) + 4.8<em />

<em />

The initial volume is when <em>t</em> = 0. Evaluate:

\displaystyle V(0) = 0.1 ((0) - 10) + 4.8 = 3.8

There was initially 3.8 liters of water.

Part C)

To find how long it will take for the tank to be completely filled given its maximum capacity of 60 liters, we can let V(t) = 60 and solve for <em>t</em>. Hence:

60 = 0.1(t - 10) + 4.8

Subtract:

55.2 = 0.1(t - 10)

Divide:

552 = t - 10

Add. Therefore:

t = 562\text{ minutes}

It will take 562 minutes for the tank to be completely filled.

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