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gogolik [260]
3 years ago
12

In a pile of coins there are 7 more quarters than nickels. If there is a total of$2.65 in coins, how many quarters are there?

Mathematics
2 answers:
Alinara [238K]3 years ago
6 0
<span>A quarter is equivalent to 25 cents or $0.25 and a nickel is equal to 5 cents or $0.05. In the given in this item, if there are x nickels then, there are x + 7 quarters. With these and the total amount known, we can now compute for the value of x.
                 (x)(0.05) + (x + 7)(0.25) = 2.65
 Simplifying,
             0.05x + 0.25x + 1.75 = 2.65
 Simplifying further,
                0.3x = 0.9
 The value of x from the equation is 3. Hence, there are 10 quarters.</span>
Cloud [144]3 years ago
3 0

Answer:

NONE

Step-by-step explanation:

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Cube root 0.216 to get your answer

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6 0
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Suppose a horticulturist measures the aboveground height growth rate of four different ornamental shrub species grown in a green
torisob [31]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The decision is to <u>reject</u> the <u> null hypothesis</u> at a significant level of <u>significance </u> \alpha  = 0.05 There is <u>sufficient </u> evidence to conclude that <u>at least one of the population mean</u>  is <u>different from</u>  <u>at least of the population</u>  

Step-by-step explanation:

From the question we are told that the claim is

     The mean growth rates of all four species are equal.

The  null hypothesis is  

             H_o  :  \mu _1 =  \mu_2 = \mu_3  =  \mu_4

Th alternative hypothesis is    

             H_a: at \ least \ one \ of \  the \  means \ is \not\ equal

From question the p-value is p-value  =  0.015

  And since the p-value <  \alpha so the null hypothesis will be rejected

So  

   The decision is to <u>reject</u> the <u> null hypothesis</u> at a significant level of <u>significance </u> \alpha  = 0.05 There is <u>sufficient </u> evidence to conclude that <u>at least one of the population mean</u>  is <u>different from</u>  <u>at least of the population</u>  

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