The formula is
A=p (1+r/k)^kt
A future value 3000
P present value 150
R interest rate 0.025
T time?
3000=150 (1+0.025/12)^12t
Solve for t
3000/150=(1+0.025/12)^12t
Take the log
Log (3000/150)=log (1+0.025/12)×12t
12t=Log (3000/150)÷log (1+0.025/12)
T=(log(3,000÷150)÷log(1+0.025÷12))÷12
T=119.95 years
Answer:
290
Step-by-step explanation:
First, add two digit number from them.
50 + 30 = 80
Second, add the last two numbers.
6 + 4 = 10
So, add these two results.
80 + 10 = 90
Final, all of theses results are added to three digit number of second number.
So, final result is
200 + 90 = 290
Rational due to it’s a multiple
Let x = 0.25555…
10x=2.555…
9x=2.3
90x=23
x=23/90