Answer:
A system of linear equation could only have 1 solution. This is because the straight lines will only have to meet, cross, or intersect each other once.
A system of linear equation could only have 1 solution. This is because the straight lines will only have to meet, cross, or intersect each other once.
There are many different methods in arriving to the final answer. However, errors cannot be perfectly avoided. One of these errors to mistakenly identify equations as linear. It is important that we know that the equations we are dealing with are of exact or correct characteristics.
Also, if she had used substitution method, she might have mistakenly taken the value of one variable for the other.
Answer:
3 bags per weekday
Step-by-step explanation:
Total bags of leaves at the end of the week = 26 bags
Bags of leaves she fills over the weekend = 11 bags
Bags of leaves she fills during weekdays = x bags
Total bags of leaves at the end of the week = Bags of leaves she fills over the weekend + Bags of leaves she fills during weekdays
26 = 11 + x
Subtract 11 from both sides
26 - 11 = 11 - 11 + x
15 = x
x = 15 bags
If she fills the same number of bags with leaves on each of the 5 weekdays.
how many bags she filled each weekday.
Bags she filled each weekday = Total Bags of leaves she fills during weekdays / 5 weekdays
= 15 bags / 5 weekdays
= 3 bags per weekday
use a calculator instead of asking
Answer:
H0 : μ = 4.50
H1 : μ > 4.50
Test statistic = 1.525
we conclude that there is no sufficient evidence to conclude that the mean wait time for customers is longer than 4.50.
Step-by-step explanation:
H0 : μ = 4.50
H1 : μ > 4.50
Test statistic :
(xbar - μ) ÷ s/sqrt(n)
(4.94 - 4.50) ÷ 2.10/ sqrt(53)
0.44 / 2.10/ sqrt(53)
= 1.525
α = 1 - 98% = 0.02
Decision region :
Reject H0 ; if Pvalue < α
Pvalue = p(Z < 1.525) = 0.936
Pvalue = 0.936
Since Pvalue > α ; We fail to reject H0
Hence, we conclude that there is no sufficient evidence to conclude that the mean wait time for customers is longer than 4.50.
