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algol [13]
4 years ago
6

Find the exact values of sin A and cos A. Write fractions in lowest terms. A right triangle ABC is shown. Leg AC has length 24,

leg BC has length 32, and hypotenuse AB has length 40.

Mathematics
2 answers:
Airida [17]4 years ago
6 0

In this question , it is given that

A right triangle ABC is shown. Leg AC has length 24, leg BC has length 32, and hypotenuse AB has length 40.

And we have to find the values of sin A and cos A .

sin A  = \frac{opposite}{hypotenuse} = \frac{32}{40}

sin A = \frac{4}{5}

And

cos A = \frac{adjacent}{hypotenuse} = \frac{24}{40}

cos A = \frac{3}{5}

And these are the required values of sin A and cos A .

svetoff [14.1K]4 years ago
3 0
Sin A = 32/40 = 4/5

cos A = 24/40 = 6/10 = 3/5
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