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Phantasy [73]
3 years ago
14

Given that g(x)=3x²-5x+7 find each of the following

Mathematics
1 answer:
melomori [17]3 years ago
5 0
G(x) = 3x² - 5x + 7

b) g(-2) ==> Substitude -2 into x

g(-2) = 3(-2)² - 5(-2) + 7
g(-2) = 12 + 10 + 7
g(-2) = 29

c) g(4) ==> Substitude 4 into x

g(4) = 3(4)² - 5(4) + 7
g(4) = 48 - 20 + 7
g(4) = 35

d) g(-x) ==> Substitude -x into x

g(-x) = 3(-x)² - 5(-x) + 7
g(-x) = -3x² + 5x + 7

e) g(1 - t) ==> Substitude 1 - t into x

g(1 - t) = 3(1 - t)² - 5(1 - t) + 7
g(1 - t) = 3(1 - 2t + t²) - 5 + 5t + 7
g(1 - t) = 3 - 6t + 3t² - 5 + 5t + 7
g(1 - t) = 3t² - t + 5
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15 im positively sure

Step-by-step explanation:

The 6 sides are the same sides

so 6+6=12

add the 3

12+3=15

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What is 3p + 2 > -10
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Explain what a conjecture is
shusha [124]
A conjecture is like a guess, opinion, or conclusion that is based off of incomplete information.

Hope this helps!
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The first three terms of a sequence are given. Round to the nearest thousandth (if necessary).
BabaBlast [244]

Step-by-step explanation:

the introduction of a fraction tells us that we are dealing with multiplications, and therefore a geometric sequence (where every new term is created by multiplying the previous term by a constant factor, the ratio r).

I think your teacher made a mistake, or you made one when typing the question in here.

there is no factor r that creates

15×r = 9

and

9×r = 5/27

it would mean that

15 × r² = 5/27

r² = 5/27 / 15 = 5/27 × 1/15 = 5/405 = 1/81

r = 1/9

but 15 × 1/9 = 5 × 1/3 = 5/3 is NOT 9

and 9 × 1/9 = 9/9 = 1 is NOT 5/27

so, this can't be right.

on the other hand

15 × r = 9

r = 9/15 = 3/5

and then

9 × 3/5 = 27/5

so, either the sequence should have been

15, 5/3, 5/27

or (and I suspect this to be true)

15, 9, 27/5

under that assumption we have

s1 = 15

r = 3/5

sn = sn-1 × r = s1 × r^(n-1) = 15 × (3/5)^(n-1)

s10 = 15 × (3/5)⁹ = 15 × 19683/1953125 =

= 3 × 19683/390625 = 59049/390625 =

= 0.15116544 ≈ 0.151

6 0
2 years ago
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