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NNADVOKAT [17]
3 years ago
12

Help Please!!!!! No Links

Mathematics
2 answers:
Tema [17]3 years ago
7 0
What is wrong with the person that answered?! Go to therapy you disgusting cockroach
Alexandra [31]3 years ago
4 0
Hey ok so for A the answer is 1.14 and for b it’s 0.9 hope this helps have a nice day
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The sides of a triangle are in the ratio 3:4:5 what is the length of each side if the perimeter of the triangle is 90 cm?
polet [3.4K]

Answer:

The answer to your question is:

side 1 = 22.5 cm

side 2 = 30 cm

side 3 = 37.5 cm

Step-by-step explanation:

 ratio = 3:4:5

Perimeter = 90 cm

First we get the sum of the numbers of the proportions

                          3 + 4 + 5 = 12

now divide the perimeter by the number of parts (12)

             

                           90 / 12 = 7.5

Side 1 = 3(7.5) = 22.5 cm

Side 2 = 4(7.5) = 30 cm

Side 3 = 5(7.5) = 37.5 cm

     Perimeter = 22.5 + 30 + 37.5 = 90 cm

7 0
3 years ago
WHAT IS THE ANSWER??
Nookie1986 [14]

Steps to solve:

3/x+2 - √x-3 when x = 19

~Substitute

3/19+2 - √19-3

~Simplify

3/21 - √16

~Simplify

1/7 - 4

~Subtract

-3 6/7

Best of Luck!

5 0
4 years ago
An equation has solutions of m= -5 and m = 9. Which could be the equation?
boyakko [2]

Answer:

(m+5)(m-9)=0

Step-by-step explanation:

you set each of them equal to zero,

m+5=0

m-9=0

and solve for 'm'

6 0
4 years ago
Read 2 more answers
What is -15.7 - (-8.2)?
cestrela7 [59]

Answer:

-7.5

Step-by-step explanation:

I used a calculator

8 0
3 years ago
Read 2 more answers
Prove that : sinA/1+cosA + 1+cosA/sinA=2cosecA​
tekilochka [14]

Step-by-step explanation:

\frac{sinA}{1+cosA} +\frac{1+cos}{sinA} =2cosec\\\\\\\frac{sin^{2}A+(1+cos)^{2}  }{sinA(1+cosA)} \\\\

\frac{sin^{2}A+1+cos^{2}+2cos}{sinA(1+cosA)} \\\\ and we have sin^{2}+cos^{2} =1

so \frac{1+1+2cosA  }{sinA(1+cosA)} \\\\

\frac{2+2cosA  }{sinA(1+cosA)} \\\\

\frac{2(1+cosA)}{sinA(1+cosA)} \\\\

\frac{2}{sinA} we have \frac{1}{sin}=cosec\\

<em>Finally </em>2cosecA<em />

<em>I really hope this helps coz it took much time </em>

3 0
3 years ago
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