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NNADVOKAT [17]
3 years ago
12

Help Please!!!!! No Links

Mathematics
2 answers:
Tema [17]3 years ago
7 0
What is wrong with the person that answered?! Go to therapy you disgusting cockroach
Alexandra [31]3 years ago
4 0
Hey ok so for A the answer is 1.14 and for b it’s 0.9 hope this helps have a nice day
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A container of beads contains: 8 red beads, 6 yellow beads, and 6 green beads. A bead will be drawn from the basket and replaced
77julia77 [94]

Answer:

Because of probability, a green or red bead would be drawn 14/20 times because there are 20 total beads and adding together the numbers for green and red. From this, if you multiply by 3/3 you can see that 42/60 times it will be a green bead. A reasonable prediction for green beads would then be 42 times. Hope it helps :D

7 0
3 years ago
Help? Please? Thank you!
sveta [45]

Answer:

independent: miles

dependent: minutes/hours

Step-by-step explanation:

can I see the other options for the rest?

3 0
2 years ago
Joel maps his house and his school on a coordinate grid where each unit is 1 block. His school is at (-7, -2). His house is at (
zhenek [66]

Answer:

10 blocks

Step-by-step explanation

check the image attached, the y coordinate of  his school and house are the same that is, -2 so all we have to do is check the distance between x coordinates

that is , -7 and 3

distance between school and his house = 3 - (-7) = 10 blocks

3 0
3 years ago
Read 2 more answers
A particle moves along a line with acceleration a (t) = -1/(t+2)2 ft/sec2. Find the distance traveled by the particle during the
amm1812

Answer:

s(t)=(ln|7|+ln|2|)\,ft

Step-by-step explanation:

Acceleration is second derivative of distance and are related as:

a(t)=\frac{d^2s}{dt^2}\\\\\frac{d^2s}{dt^2}=\frac{-1}{(t+2)^2}\\

Integrating both sides w.r.to t

v(t)=\frac{ds}{dt}=\frac{1}{t+2} +C\\

Using initial value

v(0)=\frac{1}{2}\\\\\frac{1}{2}=\frac{1}{0+2} +C\\\\C=0\\\\\frac{ds}{dt}=\frac{1}{t+2}

We have to calculate the distance covered in time interval [0,5], so:

\int\limits^5_0 \frac{ds}{dt}=\int\limits^5_0 {\frac{1}{t+2}} \, dt\\\\s(t)=[ln|t+2|]^5_0\\\\s(t)=ln|5+2|+ln|0+2|\\\\s(t)=(ln|7|+ln|2|)\,ft

3 0
3 years ago
What is<br> 3x-y=9<br> 2x-y=7
svet-max [94.6K]

Answer:

x=2 and y= -3

Step-by-step explanation:

This is a simultaneous equation. To solve this type of equation, there are three methods; substitution, Elimination and Graphical.

But here, we would be using the substitution method.

3x-y=9 Equation 1

2x-y=7. Equation 2

Getting y from equation 2, we have

-y= 7-2x

Multiply both sides by -

y= 2x-7 Equation 3

Substituting y for 2x-7 in equation 1, we have

3x- (2x-7)=9

3x-2x+7=9

x+7=9

x=9-7

x=2

Substituting x as 2 in equation 3

y=2x-7

y= 2(2)-7

y= 4-7

y= -3

5 0
3 years ago
Read 2 more answers
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