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aivan3 [116]
3 years ago
9

16.437 rounded to the neatest tenth is 16.4 true or false

Mathematics
2 answers:
Ainat [17]3 years ago
7 0
Answer=True

When rounding 16.437 to the nearest tenth, we need to look to the hundreds place.

16.437

The number 3 is in the hundreds place

The rules of rounding are:

If the number is 5 or greater, then you round up.

If the number is 4 or less, Then you round down.

Since 3 is less than 4, we would round down. So...

16.437 becomes 16.4
Pavlova-9 [17]3 years ago
7 0
It is true because after the decimal the digit is in the tenths catagory then hundreths and thousandths etc. That is why it is tenths.
:)
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DerKrebs [107]

Answer:

distance across the pond: 13 yd

distance walked by Garret: 12 yd

Step-by-step explanation:

Data:

  • distance across the pond: x yd
  • distance walked by Sandy: 5 yd
  • distance walked by Garret: x-1 yd

A right triangle is formed where the distance across the pond is the hypotenuse. From Pythagorean theorem:

x² = 5² + (x-1)²

x² = 25 + x² - 2x + 1

0 = 26 - 2x

x = 13

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3 years ago
Rectangle J'K'L'M' shown on the grid is the image of rectangle JKLM after transformation. The same transformation will be applie
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Translation is (h, k)→(h+7, k+5)
T is (6, -6)
So T' is (6+7, -6+5)=(13, -1)
4 0
3 years ago
Read 2 more answers
What is 6 tenths 20 hundredths 4 ones and 50 hundreds
Elina [12.6K]

Answer:

The answer is 25064.

Step-by-step explanation:

<u>There is a mistake in the question so the correct is below:</u>

What is 6 tenths 20 thousandths 4 ones and 50 hundreds.

Now, to solve it:

So, we arrange it in sequence:

20 thousandths 50 hundreds 6 tenths and 4 ones.

Now,

20 thousandths = 20 <u>000</u>

50 hundreds      = 50 <u>00</u>

6 tenths              = 6 <u>0</u>

4 ones                = 4

Thus, 20 thousandths 50 hundreds 6 tenths and 4 ones is :

20,000 + 5000 + 60 + 4.

= 25064.

Therefore, the answer is 25064.

3 0
3 years ago
Whats the roots of the following three problems:
klemol [59]

QUESTION 1

The given function is

f(x)=\frac{(x-3)(x-1)}{(x-1)(x+2)}

We simplify to get;

f(x)=\frac{x-3}{x+2}

This function is equal to zero when x-3=0

\Rightarrow x=3

QUESTION 2

The given function is

f(x)=\frac{5x^2-10x+5}{2x^2-5x+3}

f(x)=\frac{5(x^2-2x+1)}{2x^2-5x+3}

We factor to get;

f(x)=\frac{5(x-1)^2}{(2x-3)(x-1)}

f(x)=\frac{5(x-1)}{(2x-3)}

This function equals zero when

5(x-1)=0

x=1

QUESTION 3

The given function is

f(x)=\frac{x^3-8}{x^2-6x+8}

We factor to get,

f(x)=\frac{(x-2)(x^2+2x+4)}{(x-2)(x+4)}

f(x)=\frac{x^2+2x+4}{x+4}

The function equals zero when x^2+2x+4=0

D=b^2-4ac

D=2^2-4(1)(4)

D=-12

Hence the equation has no real roots.

The complex roots are

x=-\sqrt{3}i-1 or x=-1+\sqrt{3}i

4 0
3 years ago
In a jar, there is a green, a blue, and a red marble. You draw (with replacement) a marble from the jar until you get the green
denpristay [2]

Answer:

The value is P( X = m ) = (\frac{2}{3} )^{m-1 } * \frac{1}{3}

Step-by-step explanation:

From question we are told that

   The number of types of marbles present jar is n  =  3

Generally the probability of drawing a green marble is  

     P(g) =  \frac{1}{3}

Generally the probability of drawing a marble that is not green is  

     P(g') =  1 - \frac{1}{3} = \frac{2}{3}

From the question we are told that there will be continuous drawing of marbles from the jar (in such a way that after each marble is drawn it is being replaced) until a green marble drawn

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it then means that for m - 1 times the marbles where drawn a green marble was not obtain.

Generally the probability drawing m times is mathematically is mathematically represented as

    P( X = m ) = (P(g'))^{m-1 } * P(g)

=>  P( X = m ) = (\frac{2}{3} )^{m-1 } * \frac{1}{3}

7 0
3 years ago
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